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ioda
2 years ago
5

A carpenter charges $630 for 14 hours of work. She charges the same

Mathematics
1 answer:
san4es73 [151]2 years ago
4 0

the graph would go up 45$ per hour of work if she is charging a per hour rate

Step-by-step explanation:

becouse she charges 630$ per 14 hours you would do 630÷14 which =45$

the 45 represents the hourly rate

the graph should spike every hour mark.

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Vadim26 [7]

Answer:

(a) The solution to the differential equation is x = A_0Coswt + Ce^(-kx)

(b) The initial condition t > 0 will not make much of a difference.

Step-by-step explanation:

Given the differential equation

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(a) To solve the differential equation, first separate the variables.

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Integrating both sides, we have

ln(x - A) = -kt + c

x - A = Ce^(-kt) (Where C = ce^(-kt))

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Now, we put A = A_0Coswt

x = A_0Coswt + Ce^(-kx) (Where C is constant.)

And we have the solution.

(b) Since temperature t ≠ 0, the initial condition t > 0 will not make much of a difference because, Cos(wt) = Cos(-wt).

It is not any different from when t < 0.

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3 years ago
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Step-by-step explanation:

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