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natita [175]
3 years ago
8

I cant figure out what equation to do​

Mathematics
1 answer:
Dimas [21]3 years ago
6 0

Answer: Your answer is 48%

Step-by-step explanation:

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What is social stratification?
MrRissso [65]

Answer:

The answer is B

Step-by-step explanation

It's a system ranking people in a hierarchy

3 0
2 years ago
95×2 the answer to problem is​
KengaRu [80]

95 times 2 is 190.

90 times 2 is 180, and 5 times 2 is 10.

180 + 10 = 190.

3 0
3 years ago
Read 2 more answers
The olympics are held every four years. In 2016, the XXXI olympiad were held in Rio de Janeiro,Brazil. Determine the year of the
Anna007 [38]

Answer:

First Olympic held in year 1896.

Step-by-step explanation:

Number of Olympiad held in Rio = XXXI = 31st

Difference of years in two consecutive Olympiads = 4 years

Number of years spent in 31 Olympiads can be calculated by,

Number of years spent = (n - 1)d

Here n = number of Olympiads held

d = difference between two consecutive Olympiads

Number of years spent till 31st Olympiads = (31 - 1)×4

                                                                      = 120 years

Therefore, 1st Olympiad held in the year = 2016 - 120

                                                                   = 1896

6 0
3 years ago
If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac
mezya [45]

There are \binom{52}4 ways of drawing a 4-card hand, where

\dbinom nk = \dfrac{n!}{k!(n-k)!}

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are \binom{13}4 ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are \binom41 ways of picking a card of any given value. We draw 4 cards from the deck, so there are \binom41^4 possible hands in which each card has a different value.

Then there are \binom{13}4 \binom41^4 total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761

4 0
2 years ago
If log 2 = a and log 5<br> b then<br> log<br> 32/125
sveta [45]

Answer:

log(32/125)

=log32 - log125 [log(x/y)=log(x) - log(y)]

=log(2)^2 - log(5)^3

=2log2-3log5 [log(x)^p=p log x]

=2a-3b

4 0
3 years ago
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