Evaluate 7^2 PLEASE HELP ME

Dpf-sdzm-tdo = common girls

arlik [135]

Answer: I don’t understand

Step-by-step explanation:

Next time actually ask something about college math

6 0

3 years ago

Sid and Libby are planning to sell pies at a local fair. They spend $200 to rent a table at the fair. Their costs for ingredient

pychu [463]

Sid and Libby are planning to sell pies at a local fair.
=> $200 to rent a table at the fair.
=> $3.00 per pie costs for ingredients, other supplies, baking, and packaging
They plan to sell the pies for $8 each.
Let's find out how many pies will they be selling inorder to gain profit
=> 200 + 3.00(n) = 8(n), where n is the number of pie.
Let's try 40
=> 200 + 3(40) = 8 (40)
=> 320 = 320
=> 200 + 3(41) = 8 (41)
=> 323 = 328
Thus, in their 41st pie, they will get a profit

4 0

3 years ago

Andy takes an average of 12 breaths per minute About how many breaths did Andy take by the time he turned 13 years old?

Diano4ka-milaya [45]

6832800 breathes in 13 years exactly

6 0

3 years ago

Which expression represents the product of s and 39? A=39-s B=39÷s C=39s D=39+s

Degger [83]

The answer would be c because it means Multiply and whenever a variable is next to a number in this case 39s then that means it a multiplication
So C. 39s

4 0

3 years ago

You are working in a primary care office. Flu season is starting. For the sake of public health, it is critical to diagnose peop

Aleksandr-060686 [28]

Answer:

E. 0.11

Step-by-step explanation:

We have these following probabilities:

A 10% probability that a person has the flu.

A 90% probability that a person does not have the flu, just a cold.

If a person has the flu, a 99% probability of having a runny nose.

If a person just has a cold, a 90% probability of having a runny nose.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem, we have that:

What is the probability that a person has the flu, given that she has a runny nose?

P(B) is the probability that a person has the flu. So P(B) = 0.1.

P(A/B) is the probability that a person has a runny nose, given that she has the flu. So P(A/B) = 0.99.

P(A) is the probability that a person has a runny nose. It is 0.99 of 0.1 and 0.90 of 0.90. So

$P(A) = 0.99*0.1 + 0.9*0.9 = 0.909$

What is the probability that this person has the flu?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.1*0.99}{0.909} = 0.1089 = 0.11$

The correct answer is:

E. 0.11

5 0

3 years ago