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Mademuasel [1]
3 years ago
11

How do I find x and y

Mathematics
1 answer:
Usimov [2.4K]3 years ago
3 0
First you would have to find the third angle in the triangle which you would do by adding 63+61 and subtracting the resulting number from the total degrees in a triangle. From there, you would calculate x and y using the knowledge that angles on a line equal 180.
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Select the locations on the number line to plot the points 9/2 and −7/2 .
Alex_Xolod [135]

9/2 would be on the right -7/2 will be on the left hope i helped

3 0
3 years ago
Read 2 more answers
-7 exponent 2 - x + 6x + x exponent 2
s2008m [1.1K]

Answer:

x²+5x-49

Step-by-step explanation:

-7² -x+6x+x²

combine like terms

-x+6x is 5x

simplify -7²  is -49

now rewrite the equation

x²+5x-49

5 0
2 years ago
Read 2 more answers
Please help asap! (:
MAXImum [283]
Hello!

You can only add variables with the same base and exponent

8u^3 + 4u^3 = 12u^3
8u^2 + 0 = 8u^2
0 + -6u = -6u
6 + 3 = 9

Put the sums together

12u^3 + 8u^2 - 6u + 9

The answer is D) 12u^3 + 8u^2 - 6u + 9

Hope this helps!

6 0
3 years ago
Read 2 more answers
Calculate the axis of symmetry in the equation Y = (x+1) (x-4)
algol [13]

Answer:

<em>Every </em><em>parabola </em><em>has </em><em>a </em><em>turning</em><em> point</em><em> </em><em>called </em><em>the </em><em>axis</em><em> of</em><em> symmetry</em><em>,</em><em>so </em><em>for </em><em>this </em><em>question</em><em> </em><em>you </em><em>just</em><em> </em><em>have </em><em>to </em><em>find </em><em>the </em><em>turning</em><em> </em><em>points</em>

<em>x </em><em>turning</em><em> </em><em>point</em><em>=</em><em> </em><em>-b/</em><em>2</em><em>a</em><em>,</em><em>and </em><em>the </em><em>y </em><em>turning</em><em> </em><em>point</em><em> </em><em>is </em><em>gotten</em><em> </em><em>by </em><em>replacing</em><em> </em><em>the </em><em>value </em><em>of </em><em>x </em><em>in </em><em>the </em><em>equation</em>

<em>y=</em><em>(</em><em>x+</em><em>1</em><em>)</em><em>(</em><em>x-4)</em>

<em> </em><em> </em><em>=</em><em>x^</em><em>2</em><em>-</em><em>3</em><em>x</em><em>-</em><em>4</em>

<em>a </em><em>is </em><em>1</em><em>,</em><em>b </em><em>is </em><em>-</em><em>3</em><em> </em><em>and </em><em>c </em><em>is </em><em>-</em><em>4</em>

<em>x=</em><em> </em><em>-</em><em>(</em><em>-</em><em>3</em><em>)</em><em>/</em><em>2</em><em>(</em><em>1</em><em>)</em>

<em> </em><em> </em><em>=</em><em>1</em><em>.</em><em>5</em>

<em>and </em><em>y=</em><em>x^</em><em>2</em><em>-</em><em>3</em><em>x</em><em>-</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>.</em><em>5</em><em>^</em><em>2</em><em>-</em><em>3</em><em>(</em><em>1</em><em>.</em><em>5</em><em>)</em><em>-</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>-</em><em>6</em><em>.</em><em>2</em><em>5</em>

<em>therefore</em><em> </em><em>the </em><em>axis </em><em>of</em><em> symmetry</em><em> is</em><em> (</em><em>1</em><em>.</em><em>5</em><em>,</em><em>-</em><em>6</em><em>.</em><em>2</em><em>5</em><em>)</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

6 0
2 years ago
1. How many real solutions does the quadratic equation x?+9x= -8 have?​
likoan [24]

Answer:

This quadratic equation has 2 solutions.

Step-by-step explanation:

I assume the '?' in your question is meant to be power 2 (²), or else it would not be a quadratic equation. You could write it using the superscript version of 2.

We can solve this equation by expressing it in the form: ax² + bx + c

x² + 9x= -8

x² + 9x + 8 = 0

Now if you know the discriminant, you can simply plug in your values of a, b, and c to see how many solutions there are.

In this case, you would not need the discriminant as there are whole-number factors and hence this can simply be factorised.

x² + 9x + 8 = 0

(x + 8)(x + 1) = 0

For this equation to be true (= 0), x can equal -8 OR -1.

Hence, this quadratic equation has 2 solutions.

5 0
2 years ago
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