Answer:
The maximum volume of the open box is 24.26 cm³
Step-by-step explanation:
The volume of the box is given as 
, where 
and 
.
Expand the function to obtain:
Differentiate wrt x to obtain:
To find the point where the maximum value occurs, we solve
Discard x=3.54 because it is not within the given domain.
Apply the second derivative test to confirm the maximum critical point.
, 
This means the maximum volume occurs at 
.
Substitute into to get the maximum volume.
The maximum volume of the open box is 24.26 cm³
See attachment for graph.
- don't know what you mean, but maybe the graph?
Answer:
V = 500 pi in^3
or approximately 1570 in ^3
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h where r is the radius and h is the height
The diameter is 10. so the radius is d/2 = 10/2 =5
V = pi (5)^2 * 20
V = pi *25*20
V = 500 pi in^3
We can approximate pi by 3.14
V = 3.14 * 500
V = 1570 in ^3
Ans
I = sqrt(P/R)
Step-by-step explanation:
You divide both sides by R first
P/R = I^2 R/R
So,
I^2 = P/R
take the square root of both sides
I = sqrt(P/R)
Hey hey hey I see no picc
