3 years ago

A number is k units to the left of 0. What's the location on a number line

Mathematics

1 answer:

luda_lava [24]3 years ago

7 0

The answer to the question listed above is -11

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Using separation of variables technique, solve the following differential equation with initial condition y'= e sinx and y(pi) =

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$e^{-0}=\cos \pi +C\\1=1+C\\C=0\\\\\boxed{\boxed{e^{-y}=\cos x}}$

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"whats the area of a circle with a circumference of 50.24 units"<br>pls help:)

Umnica [9.8K]

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200.96 units^2

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2 years ago

Read 2 more answers

Find p(-3) if p(x)= 4x^3 - 5x^2 + 7x - 10.

andriy [413]

Answer:

p(-3) = -184

Step-by-step explanation:

p(-3) = 4(-3)^3 - 5(-3)^2 + 7(-3) -10

= 4(-27) - 5(9) - 21 - 10

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replace x with -3 and then solve

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2 years ago

Complex root of x^2+3x+9=0

Luden [163]

$\text{Quadratic formula}$

$ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}$

-----------------------------------------------------------------------

$x^2+3x+9=0\\\\a=1;\ b=3;\ c=9\\\\\Delta=3^2-4(1)(9)=9-36=-27\\\\\sqrt\Delta=\sqrt{-27}=\sqrt{(27)(-1)}=\sqrt{27}\cdot\sqrt{-1}=\sqrt{9\cdot3}i=\sqrt9\cdot\sqrt3i=3\sqrt3i$

$x_1=\dfrac{-3-3\sqrt3i}{2(1)}=-\dfrac{3}{2}-\dfrac{3\sqrt3}{2}i\\\\x_2=\dfrac{-3+3\sqrt3i}{2(1)}=-\dfrac{3}{2}+\dfrac{3\sqrt3}{2}i$

$i=\sqrt{-1}$

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3 years ago