<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
Answer: 5.3
Step-by-step explanation: Do 9.8 (Friend swim depth) - 4.5 (dolphin jump height) to get your answer.
Step-by-step explanation:
Multiplication property of order
answer:C
p=-45
Answer:
Step-by-step explanation:
a (2³)² = 2³ˣ² = 2⁶
b (7⁰)¹ = 7⁰ˣ¹ = 7⁰ = 1
c (5⁶)³ = 5⁶ˣ³ = 5¹⁸
d (6²)⁴ = 6²ˣ⁴ = 6⁸
e (8³)⁴ = 8³ˣ⁴ = 8¹²
f (4³)² = 4³ˣ² = 4⁶
g (9¹)² = 9¹ˣ² = 9² = 81
h (3⁷)² = 3⁷ˣ² = 3¹⁴
i (10²)³ = 10²ˣ³ = 10⁶
j (11²)⁴ = 11²ˣ⁴ = 11⁸
This would mean that she has been in school for about 1,000 days. Thus, we need to figure out the amount of days she would have went to school within the week. This would normally be 5 days within the 7.
5/100 x 1000 is 714.28
When rounded to the nearest ten, it would end up at 710.
