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alexdok [17]
2 years ago
5

What is the surface area of the square pyramid?

Mathematics
2 answers:
levacccp [35]2 years ago
6 0
The surface area would be 16 square meters!
konstantin123 [22]2 years ago
4 0
It would be 16 square meters
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Check whether 2-3x is a factor of (x)2 -x+1
sergejj [24]

Answer:

no

Step-by-step explanation:

if it was a factor then, 2-3x = 0

x= 2/3

putting x = 2/3 in eqn,

(2/3)^2 - 2/3 +1 =7/9....so it is not a factor

5 0
3 years ago
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The solution set for the equation of a circle is all the_____ on the circle.
zalisa [80]
The answer to your question is ( points ).
5 0
1 year ago
What is the value of the expression? 56−(18÷34) as a fraction in simplest form
marta [7]
The value of the expression in simplest form is: 55 8/17.

Hope this helps! :D

~PutarPotato
7 0
3 years ago
In a recent poll, 778 adults were asked to identify their favorite seat when they fly, and 492 of them chose a window seat. Use
seropon [69]

Answer:

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

p_v =P(Z>7.36)=9.19x10^{-14}  

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

Step-by-step explanation:

1) Data given and notation

n=778 represent the random sample taken

X=492 represent the people that chose a window seat.

\hat p=\frac{492}{778}=0.632 estimated proportion of people that chose a window seat.

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the majority of adults prefer window seats when they fly:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.632 -0.5}{\sqrt{\frac{0.5(1-0.5)}{778}}}=7.36  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>7.36)=9.19x10^{-14}  

5) Conclusion

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

6 0
3 years ago
I need help with this can you please help me?
Vikki [24]
2. 12x5y
 3.7.402 x 10^6
4. 2.36 x 10^2, 2.36 x 10^3, 23.6 x 10^3
4 0
3 years ago
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