They communicate their result to the scientific community- so to speak
The speed of water can be split into vertical and horizontal speed components:

Due to the force of gravity, the y component will be parabolic. The x component will be linear:

To find when the water hits the ground 2.5m away, set y= 0 and x = 2.5
Coulomb's law:
Force = (<span>8.99×10⁹ N m² / C²<span>) · (charge₁) · (charge₂) / distance²
= (</span></span><span>8.99×10⁹ N m² / C²<span>) (1 x 10⁻⁶ C) (1 x 10⁻⁶ C) / (1.0 m)²
= (8.99×10⁹ x 1×10⁻¹² / 1.0) N
= 8.99×10⁻³ N
= 0.00899 N repelling.
Notice that there's a lot of information in the question that you don't need.
It's only there to distract you, confuse you, and see whether you know
what to ignore.
-- '4.0 kg masses'; don't need it.
Mass has no effect on the electric force between them.
-- 'frictionless table'; don't need it.
Friction has no effect on the force between them,
only on how they move in response to the force.
</span></span>
Answer:
180.4 m
Explanation:
The package in relation to the point where it was released falls a certain distance that is calculated by applying the horizontal motion formulas , as the horizontal speed of the plane and the height above the ground are known, the time that It takes the package to reach its destination and then the horizontal distance (x) is calculated from where it was dropped, as follows:

h = 100 m
x =?
Height formula h:

Time t is cleared:


t = 4.51 sec
Horizontal distance formula x:

x = 40 m / sec x 4.51 sec
x = 180.4 m
The answer would be D. <span>The tortoise moved at a constant velocity throughout the race; the hare stopped to rest periodically.
Hope this helped. Good luck!</span>