heat conduction is cut off by vacuum.
metal cover block light thereby protecting radiation
<span>Applied Force Direction vector = [0,1,3]
force F = j + 4k
torque is t = 100 Newton-meters = r x F
Wrench is 0.5 meters long on positive side of the y-axis, r = 0.6 = [0,0.6,0]
We know torque |t| = |r x F| = |r| x |F| sin theta
r x F = |r| x |F| cos theta
r x (j + 3k) = |r| x |j + 3k| cos theta
=> [0,0.6,0] [0,1,3] = 0.6 x squareroot of ((0)^2 + (1)^2 + (3)^2) cos theta
=> 0.6 = 0.6 x squareroot of (1 + 9) cos theta
=> cos theta = 1 / squareroot of (10)
Calculationg the sin theta,
sin theta = squareroot of (1 - (1 / squareroot of (10))^2) = squareroot of (9/10)
sin theta = 3 / squareroot of (10)
Substituting the values,
|T| = |r| x |F| sin theta => 100 = |0.6| x |F| x 3 / squareroot of (10)
|F| = (100 x squareroot of (10)) / 1.8
|F| = (1000 / 18) x squareroot of (10)
Magnitude of force |F| = 55.55 x squareroot of (10)</span>
Answer:
Explanation:
In multiplications or divisions, the result must be written using a number of significant figures equal to the smallest number of significant figures contained in the original numbers.
For instance, in this case the two numbers are:
3278 --> 4 significant figures
42 --> 2 significant figures
So, the product must be written using 2 significant figures.
Calculating the product, we get:
Therefore, using 2 significant figures only, the result is
It measures<span> the relative humidity in the atmosphere through the use of two thermometers. The first, a dry bulb thermometer, is used to </span>measure<span> the temperature by being exposed to the air. The second, a wet bulb thermometer,</span>measures<span> temperature by having the bulb dipped in a liquid.</span>
Potential difference is the work done per unit charge. A potential difference of 1 V<span>means that 1 joule of work is done per coulomb of charge. ( </span>1 V<span> = 1 J C</span>-1<span>) Potential difference in a circuit is measured using a voltmeter which is placed in parallel with the component of interest in the circuit.</span>
