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Veseljchak [2.6K]
3 years ago
15

What is the relationship between the temperature of a star and its luminosity?

Physics
1 answer:
Sladkaya [172]3 years ago
3 0
The Luminosity of a star is proportional to its Effective Temperature to the 4th power and its Radius squared.
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What is the acceleration of a 30.0-kg go kart if the thrust of its engine is 300.0 N?
VikaD [51]

Answer : a=10\ m/s^2

Explanation :

It is given that,

Mass of the engine, m = 30 kg

Thrust is equivalent to the force acting perpendicularly and it is F = 300 N

According to Newton's second law of motion :

F = m\times a

a is the acceleration of the engine.

a=\dfrac{F}{m}

a=\dfrac{300\ N}{30\ Kg}

a=10\ m/s^2

So, the acceleration of the engine is 10\ m/s^2.

Hence, this is the required solution.

5 0
3 years ago
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The measure of how much salt will dissolve into 100g of water is _______________ .
Bingel [31]
The measure of how much salt will dissolve into 100g of water is _solution_ .
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3 years ago
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A piece of wood has a volume of 4.6 cm to the power of 3, and a mass of 3.7 g what is the density of the wood
AysviL [449]

Density is given by:

D = M/V

D = density, M = mass, V = volume

Given values:

M = 3.7g, V = 4.6cm³

Plug in and solve for D:

D = 3.7/4.6

D = 0.80g/cm³

3 0
3 years ago
What is the specific heat of an object if it takes 1200 J to raise the temperature of a 20 kg object by 6 degrees C?
ch4aika [34]

Answer:

c=10\ J/kg^{\circ} C

Explanation:

Given that,

Heat required, Q = 1200 J

Mass of the object, m = 20 kg

The increase in temperature, \Delta T=6^{\circ} C

We need to find the specific heat of the object. The heat required to raise the temperature is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{1200}{20\times 6}\\\\c=10\ J/kg^{\circ} C

So, the specific heat of the object is 10\ J/kg^{\circ} C.

5 0
3 years ago
a car takes 125 ft to brake from 60 to 0 mph. Assume that the acceleration of the Prius is constant while braking. Find how long
max2010maxim [7]

Answer:

2.84 seconds

Explanation:

t = ?

distance = 125

Velocity origianal = 60 m/hr = 88 ft/s

     AVERAGE velocity = 88/2 = 44 ft/s

44 t = 125

t = 125/44 = 2.84 s

7 0
2 years ago
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