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irakobra [83]
4 years ago
12

In a transverse wave that travels through a medium, the molecules of the medium vibrate

Physics
1 answer:
LenaWriter [7]4 years ago
4 0
<span>So we wan't to know how the molecules of the medium vibrate when a transverse wave propagates trough that medium. A transverse wave is a wave whos oscilations are perpendicular to the direction of it's propagation. So the molecules in a medium will vibrate perpendicular to the direction of propagation of the wave. So if the wave is moving in the x-direction, the molecules will vibrate in the y-z plane. The correct answer is A. at right angles to the direction in which the wave propagates. </span>
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A 50.0 kg object is moving at 18.2 m/s when a 200 N force is applied opposite the direction of the objects motion, causing it to
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Answer:

t = 1.4[s]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.

P=m*v\\or\\P=F*t

where:

P = impulse or lineal momentum [kg*m/s]

m = mass = 50 [kg]

v = velocity [m/s]

F = force = 200[N]

t = time = [s]

Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.

(m_{1}*v_{1})-F*t=(m_{1}*v_{2})

where:

m₁ = mass of the object = 50 [kg]

v₁ = velocity of the object before the impulse = 18.2 [m/s]

v₂ = velocity of the object after the impulse = 12.6 [m/s]

(50*18.2)-200*t=50*12.6\\910-200*t=630\\200*t=910-630\\200*t=280\\t=1.4[s]

3 0
3 years ago
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H = \frac{1}{2g}(v_x^2 + v_y^2)

H = \frac{1}{2(9.81)}(7.44^2 + 6.6^2)

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