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4 years ago

12

In a transverse wave that travels through a medium, the molecules of the medium vibrate

1 answer:

LenaWriter [7]4 years ago

4 0

<span>So we wan't to know how the molecules of the medium vibrate when a transverse wave propagates trough that medium. A transverse wave is a wave whos oscilations are perpendicular to the direction of it's propagation. So the molecules in a medium will vibrate perpendicular to the direction of propagation of the wave. So if the wave is moving in the x-direction, the molecules will vibrate in the y-z plane. The correct answer is A. at right angles to the direction in which the wave propagates. </span>

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Phÿśïčš<br><br>write the relation between celsius and fahrenheit scale?

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Answer:

C/100 = (F-32) / 180

or, C/5 = (F-32)/9

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relation between any two scales is given by:

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3 years ago

The property of matter that describes what it is made of

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Answer:

Miixture

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3 years ago

The resistivity of a metal increases slightly with increased temperature. This can be expressed as rho= rho0[1+α(T−T0)] , where

Stolb23 [73]

Answer:

At 81. 52 Deg C its resistance will be 0.31 Ω.

Explanation:

The resistance of wire = $R_T =\frac{\rho_T \ l}{A}$

Where $R_T$ =Resistance of wire at Temperature T

$\rho_T$ = Resistivity at temperature T $=\rho_0 \ [1 \ + \alpha\ (T-T_0\ )]$

Where $T_0 =20\ Deg\ C , \ \rho_0 = Constant, \alpha =3.9 \times 10^-^3 DegC^-1 \ (Given)$

l=Length of the wire

& A = Area of cross section of wire

For long and thin wire the resistance & resistivity relation will be as follows

$\frac{R_T_1}{R_T_2}=\frac{\rho_0(1+\alpha \cdot(T_1-2 0 )}{\rho_0(1+\alpha \cdot (T_2 -20 )}$

$\frac{0.25}{0.31}=\frac{1}{[1+\alpha(T-20)]}$

$1.24=1+\alpha (T-20)$

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3 years ago

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Naya [18.7K]

Answer:

<h2>D</h2>

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momentum = mass × velocity

From the question

mass = 2 kg

velocity/speed = 3 m/s

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momentum = 2 × 3 = 6

We have the final answer as

<h3>6 kg.m/s</h3>

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