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Tom [10]
2 years ago
7

Triangles J K L and X Y Z are shown. The length of side J is 3, the length of side K is 6, and the length of side L is 4. The le

ngth of side X is 4, the length of side Y is 4, and the length of side Z is 5.
Classify each of the triangles as acute, obtuse, or right.



Triangle JKL is
triangle.

Triangle XYZ is
triangle.
Mathematics
2 answers:
Inga [223]2 years ago
6 0

Answer:

obtuse & acute

Step-by-step explanation:

umka2103 [35]2 years ago
4 0

Answer:

The answer is below

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. Types of triangles are acute, scalene, obtuse, equilateral, isosceles and right angled triangle.

For a right angled triangle, the square of the longest side (hypotenuse) is equal to the sum of the square of the remaining two sides.

For an obtuse triangle, the square of the longest side is greater than the sum of the square of the remaining two sides.

For an acute triangle, the square of the longest side is less than the sum of the square of the remaining two sides.

In triangle JKL:

J² + L² = 3² + 4² = 25

K² = 6² = 36 > 25 (J² + L²)

Hence triangle JKL is an obtuse triangle

In triangle XYZ:

X² + Y² = 4² + 4² = 32

Z² = 5² = 25 < 32 (X² + Y²)

Hence triangle XYZ is an acute triangle.

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Galina-37 [17]

Answer:

12 i believe

Step-by-step explanation:

volume; LxWxH

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2 years ago
Describe the graph of a function g by observing the graph of the base function f ? ​
never [62]

Answer:

Choice 3 is your answer

Step-by-step explanation:

The format of the function when you move it side to side or up and down is

f(x) = (x - h) + k,

where h is the side to side movement and k is up or down.  The k is easy, since it will be positive if we move the function up and negative if we move the function down from its original position.

The h is a little more difficult, but just remember the standard form of the side to side movement is always (x - h).  If our function has moved 3 units to the left, we fit that movement into our standard form as (x - (-3)), which of course is the same as (x + 3).  Our function has moved up 5 units, so the final translation is

g(x) = f(x + 3) + 5, choice 3 from the top.

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3 years ago
In ΔАВС, m∠ACB = 90°, <br> CD<br> ⊥ <br> AB<br> m∠ACD = 30°, and AC = 6 cm. Find BD
myrzilka [38]
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3 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv
ch4aika [34]

Answer:

Part 1) The function of the First graph is f(x)=(x-3)(x+1)

Part 2) The function of the Second graph is f(x)=-2(x-1)(x+3)

Part 3) The function of the Third graph is f(x)=0.5(x-6)(x+2)

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

f(x)=a(x-c)(x-d)

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-3)(x+1)

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

-4=a(1-3)(1+1)

-4=a(-2)(2)

a=1

therefore

The function is equal to

f(x)=(x-3)(x+1)

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

f(x)=a(x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

8=a(-1-1)(-1+3)

8=a(-2)(2)

a=-2

therefore

The function is equal to

f(x)=-2(x-1)(x+3)

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-6)(x+2)

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

-8=a(2-6)(2+2)

-8=a(-4)(4)

a=0.5

therefore

The function is equal to

f(x)=0.5(x-6)(x+2)

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