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3 years ago

What is the solution of log4x − 616 = 4? x = −2 x = 2 x = 3 x = 4

1 answer:

3 0

<span>This is how to solve for log expressions.
First, do the arithmetic such that all that can be solved is in the other side, besides log.
There are different properties of log to help you solve log expressions.

log4x − 616 = 4
</span><span>log4x = 620
</span>Change how it is written to solve for x.
x^620 = 4
This makes no sense so we try again.

Or, this could be solved differently.
log 4x-6 16 = 4
(4x-6) ^4 = 16
256x - 1296 = 16
x = 5.125

Final answer: x = 5

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Which of the following is equivalent to the expression below (x+3)(x+4)

anyanavicka [17]

Answer:

Now, we can visually see that 6/8, is equivalent to 3/4, because the total height of the colored parts remains the same. Next, let's multiply the numerator 6, with 3, and the denominator 8, with 3

Step-by-step explanation:

please, and i hope that is a answer

4 0

2 years ago

Lola rode her bike for 7/10 of an hour on Saturday, and 3/5 of an hour on Sunday.

Fed [463]

Answer:

She rode 1/10 of an hour more on Saturday

Step-by-step explanation:

Take the time she rode on Sunday and subtract that from Saturday

7/10 - 3/5

Get a common denominator

7/10 - 3/5*2/2

7/10 - 6/10

1/10

She rode 1/10 of an hour more on Saturday

6 0

3 years ago

Decimal equivalent to 40 percent

Elan Coil [88]

40/100= 0.4

The answer is 0.4

Hope this helps!

6 0

3 years ago

Read 2 more answers

Use the given facts about the functions to find the indicated limit

Alika [10]

Answer:

B. -12

Step-by-step explanation:

The given limit are;

$\lim_{x \to -11} f(x)=-3$ and $\lim_{x \to -11} g(x)=4$

We want to find;

$\lim_{x \to -11} (fg)(x)=\lim_{x \to -11} f(x)\times \lim_{x \to -11} g(x)$

We substitute the given limits to obtain;

$\lim_{x \to -11} (fg)(x)=-3\times 4$

$\lim_{x \to -11} (fg)(x)=-12$

3 0

3 years ago

Evaluate the following pic

GREYUIT [131]

Answer:

1) $\sqrt{1225}+\sqrt{1024}=67$

2) $\sqrt[3]{-1331}=-11$

3) Evaluating $2:p :: p:8$ we get $p=\pm 4$

4) $x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}$

5) $\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6$

Step-by-step explanation:

1) $\sqrt{1225}+\sqrt{1024}$

Prime factors of 1225 : 5x5x7x7

Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2

$\sqrt{1225}+\sqrt{1024}\\=\sqrt{5\times5\times7\times7}+\sqrt{2\times2\times2\times2\times2\times2\times2\times2\times2\times2}\\=\sqrt{5^2\times7^2}+\sqrt{2^2\times2^2\times2^2\times2^2\times2^2}\\=5\times7+(2\times2\times2\times2\times2)\\=35+32\\=67$