$\dfrac{x}{24\sqrt{2}}=\cos45^\circ\\\\\\\dfrac{x}{24\sqrt{2}}=\dfrac{\sqrt{2}}{2}\qquad\qquad\qquad\text{(cross multiply)}\\\\\\2x=24\sqrt{2}\cdot\sqrt{2}\\\\2x=24\cdot2\quad|:2\\\\\boxed{x=24}$

7 0

2 years ago

Find the value of “O”

nexus9112 [7]

O= 4 & -4

Explain: it shows on the paper

5 0

3 years ago

3 multiply 1 over 3<br><img src="https://tex.z-dn.net/?f=3%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B3%7D%20" id="TexFormula1" title="3 \

nalin [4]

The answer to your question is 3

7 0

2 years ago

Read 2 more answers

CORRECT THE ERROR 1) 4a^(2)*3a^(5)=(4+ 3)a^(2+5)=7a^(7) // 2) x^(6)x*x^(3)=6^(4+3) //

CORRECT THE ERROR 1) 4a^(2)3a^(5)=(4+ 3)a^(2+5)=7a^(7) // 2) x^(6)xx^(3)=6^(4+3) //