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Blababa [14]
3 years ago
6

It is possible for a system of linear equations to have no solutions. true or false?

Mathematics
1 answer:
tester [92]3 years ago
7 0
Yes true because if -4=5 it is not true so it is no solution
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(2x^{2}-7x-8)+(5x^{2}-2x+9) <br> whats the sum
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-5x + 3y = -8<br> 3x - 7y= -3
AnnZ [28]

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x = 5/2   y = 3/2

Step-by-step explanation:

You need to write what the question is besides the information in the problem.  I assume the question is to find the values of x and y.

Going on that premise, Let equation (1)   be -5x + 3y = -8 and

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Lets multiply (1) by 3 and (2) by 5 and we get equations (4) and (5)

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-15x + 9y = -24

<u> 15x - 35y = -15</u>

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y = 3/2     Now substitute y = 3/2 in equation (1).  -5x + 3)(3/2) = -8

                                                                                 -5x + 9/2 = -8

                                                                                  -10x + 9 = -16

                                                                                  -10x = -25

                                                                                      x = -25/-10 = 5/2  

x = 5/2   y = 3/2

Check:  Substitute your answers into equation (2) and see if they work.

3(5/2) -7(3/2) = 15/2 - 21/2 = -6/2 = -3   Hooray!  We have the correct values for x and y that makes each equation true  

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