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adell [148]
3 years ago
11

How do you solve 2 tenths + 11 hundredths

Mathematics
2 answers:
ANTONII [103]3 years ago
7 0
Answer .31 by the way
maxonik [38]3 years ago
5 0
That would be .31

:) brainliest please:)
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Needs help with this!!!
barxatty [35]

Answer:

y^1=-1(x-1)+(1+9)

Step-by-step explanation:

y=-1x+1\ \ == > \ \ y^1=-1(x-1)+(1+9)

-1 horizontally = 1 units left (the x-axis)

9 vertically = 9 units up (y-axis)

*Black line: is the preimage

*Red line is the translation

Hope this helps!

6 0
3 years ago
A two-digit number becomes 5/6 of the reversed number obtained when the digits are interchanged. The difference between the digi
stealth61 [152]
<h3>Answer:   54</h3>

==============================================

Work Shown:

T = tens digit

U = units digit (aka ones digit)

A number like 27 is really 20+7 = 2*10 + 7*1 = 10*2 + 1*7. We have 2 in the tens digit and 7 in the units digit. So 27 can be written in the form 10T + U where T = 2 and U = 7. Reversing the digits gives 72, so T = 7 and U = 2 now. Clearly the difference between the digits 7 and 2 is not 1, so 27 or 72 is not the answer (as it's just an example).

-----------------------

Let T be larger than U. This doesn't work if T = U.

Because T is larger, saying "The difference between the digits is 1" means T - U = 1. We can isolate T to get T = U+1. We'll use this later.

-----------------------

If T > U, then the original number 10T+U reverses to the new number 10U+T and it becomes smaller. We are told that it becomes 5/6 of what it used to be.

So,

new number = (5/6)*(old number)

10U + T = (5/6)(10T + U)

6(10U + T) = 5(10T + U)

60U + 6T = 50T + 5U

60U + 6(U+1) = 50(U+1) + 5U ... plug in T = U+1

60U + 6U + 6 = 50U + 50 + 5U

66U + 6 = 55U + 50

66U - 55U = 50-6

11U = 44

U = 44/11

U = 4 is the units digit of the original number

T = U+1

T = 4+1

T = 5 is the tens digit of the original number

The original number is therefore 10T + U = 10*5+4 = 54.

We see the difference in their digits is T-U = 5-4 = 1

The reverse of 54 is 45. The number 45 is 5/6 of 54

45 = (5/6)*54

7 0
3 years ago
Lily is a botanist who works for a garden that many tourists visit. The function f(s) = 2s + 30 represents the number of flowers
Vesnalui [34]

Answer:

  A. b(w) = 80w +30

  B. input: weeks; output: flowers that bloomed

  C. 2830

Step-by-step explanation:

<h3>Part A:</h3>

For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...

  b(w) = f(s(w)) = 2(40w) +30

  b(w) = 80w +30 . . . . . . blooms over w weeks

__

<h3>Part B:</h3>

The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.

The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.

Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).

__

<h3>Part C:</h3>

For 35 weeks, the number of flowers that bloomed is ...

  b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks

7 0
2 years ago
ANSWER ASAP!
morpeh [17]

Answer:

vvvvvcvv

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Geometry math question please help
Triss [41]

A square is a figure with four equal sides and four right angles.In a square the diagonals bisect at right angles .

In the above given options option A is the right answer.

If the diagonals of any parallelogram are perpendicular then the figure is not necessarily a square.

Diagonals are perpendicular in a rhombus too.

A square and Rhombus both have diagonals that are perpendicular.

So it is not a necessary condition for a parallelogram to be a square .

The other options are right .

So option B is the right option that if diagonals are perpendicular is not sufficient to prove the figure to be a square.

6 0
4 years ago
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