Answer:
134.5 degree
Step-by-step explanation:
first find the remaining side of a triangle
BY using cosine rule
C^2=A^2+B^2-2ABcosx
apply square root both sides
√c^2 =√[4^2+10^2-2(4)(10)cos29]
C=√(116-69.96958)
C=√46.03
C=6.8
Now find angle using cosine rule
C^2=A^2+B^2-2ABcosx
10^2=4^2+6.78^2-2(4)(6.78)cosx
100=16+45.9684-54.24cosx
100=61.9684-54.24cosx
100-61.9684=-54.24cosx
(38.0316)/-54.24=(-54.4cosx)/-54.24
-0.70117=cosx
X= cos inverse of -0.70117
x=134.5 degree
I am sorry, I am so confused
I wish I could help
is it 46 ??? because i did the work and don't feel like explaining
Let y = √4+7t
then u= 4+7t
y=√u = u^½
du/dt= 7
dy/du = ½U^-½
dy/dt = du/dt • dy/du
= 7×½U^-½
= 7/2√U
= 7 / (2{√4+7t})
Answer:
d. 32.9
Step-by-step explanation:
To find c, we'll use the Law of Sines that says:

And we'll isolate a to get:

We first need to find A, which is easy. The sum of the interior angles of a triangle is 180 degrees... and we already have 2 of them, so:
A = 180 - 90 - 47.3 = 42.7
(converted 47°18' to 47.3)
Then we will plug-in the information we already have

So, let's round it to 32.9 to match the answer number D.