Answer:
Jane
Step-by-step explanation:
Since Amil has twice the size of Jane's garden, he would have more space and his 28 watermelons would not be as close and dense. Jane has 22 watermelons and her garden is half the size. Her 22 watermelons would be more dense and close to each other in a garden half the size of the neighbors.
Your answer would be sliding. hope that helped
Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
Before the fraction: -1/2, i have a negative sign
use y=mx+b
3=-1/2(2)+b
3+1=-1+b+1
4=b
check your work
0=-1/2x+4
0+4=-1/2x
(4)÷(-1/2)=(-1/2x)÷(-1/2)
-2=x
another pair is (-2,0) use this to figure out the other points, and/or the points you have in the multiple choice.
The formula in computing the area of the circle is:
A = pi (r)^2
Where r = the radius of the circle
Since you are only given the diameter of the circle, you
have to solve for its radius. The radius of the circle is half its diameter. Therefore,
the radius of the circle is 5 (10/2).
Now, you substitute the measurements to the formula:
A = 3.14 (5)^2
A = 3.14 (25)
A = 78.5 sq. units
