Answer:
33 °C
Step-by-step explanation:
Put 92 where F is in the equation, and solve for C.
92 = 1.8C +32 . . . . substitute for F
60 = 1.8C . . . . . . . . subtract 32
60/1.8 = C ≈ 33.33 ≈ 33 . . . . . divide by the coefficient of C, round the result
The temperature is about 33 °C.
Area is length x width, and perimeter is adding up all the sides together
so if it’s 32 for the perimeter, then the dimensions should be 12 and 4
12x4 is 48
12+12+4+4 is 32
Answer:
(a)2(89x+84)
(b)
Step-by-step explanation:
The dimensions of the larger rectangular field are:
- Length=5x + 12; Width
= 9x + 14.
The dimensions of the smaller rectangular soccer field are:
(a)Area of the part of the field that is outside the soccer field
=Area of the larger rectangular field - Area of the Soccer Field
=(5x+12)(9x+14)-5x(9x)
=(5x)(9x)+70x+108x+168-5x(9x)
=178x+168
=2(89x+84)
(b)Radius of the Semicircular Fountain =2x
From Part (a),
Area of the larger rectangular field - Area of the Soccer Field=178x+168
Area of the Semicircular Fountain =
Area of the Field that does not include the soccer field or the fountain.
=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

Answer:
T(2, -7) = (4, -10)
Step-by-step explanation:
T(x, y) = (x + 2, y - 3)
T(2, -7) = (2 + 2, -7 - 3)
T(2, -7) = (4, -10)