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3 years ago

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Mathematics

2 answers:

lapo4ka [179]3 years ago

8 0

Answer:

where is the question

have a good day :)

Step-by-step explanation:

mina [271]3 years ago

4 0

Where is the question ?
or maybe a picture, i don’t see anything.

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I really need help. Please answer as many as you can. I'm still figuring some out. Thanks!

Aliun [14]

Hey there, Simmonsalivia!

It seems that you are in a hurry so I will make it quick without explanation.
1) $\frac{17}{4}$ or $4 \frac{1}{4}$
2) $\frac{20}{3}$ or $6 \frac{2}{3}$
3) 11
4) $\frac{56}{15}$ or $3 \frac{11}{15}$
5) $\frac{9}{8}$ or $1 \frac{1}{8}$
6) $\frac{35}{18}$ or $1 \frac{17}{18}$
7) 4
8) $\frac{49}{12}$ or $4 \frac{1}{12}$
9) $\frac{55}{6}$ or $9 \frac{1}{6}$
10) 23 $\frac{3}{4}$ tablespoons of ground coffee.
11) She used $10 \frac{3}{8}$ amount of flour in total.
12) $\frac{16}{5}$ or $3 \frac{1}{5}$
13) 4
14) $\frac{47}{15}$ or $3 \frac{2}{15}$
15) $\frac{28}{3}$ or $9 \frac{1}{3}$
16) $\frac{68}{9}$ or $7 \frac{5}{9}$
17) $\frac{50}{9}$ or $5 \frac{5}{9}$
18) $\frac{11}{3}$ or $3 \frac{2}{3}$
19) $\frac{14}{5}$ or $2 \frac{4}{5}$
20) $\frac{16}{5}$ or $3 \frac{1}{5}$
21) Ty needed 7 paving stones.
22) Besides the top block, they needed 25 blocks to build the tower.

Thank you for using Brainly.
See you soon!

3 0

3 years ago

What is the value of t=1 3(4 x (1/2) t-1)

Aliun [14]

Answer:

t = 13 over 25 or in alternate form its t = 0.52

7 0

4 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

Which of the following points does not lie on the graph of y=1/2x+3?

Gennadij [26K]

Answer:

Step-by-step explanation:

8 0

2 years ago

The Marked price of an article is rupees 5000 .This price is 25% above the cost price. If the article is sold by allowing 10% di

Brilliant_brown [7]

Answer: 13%

Step-by-step explanation:

Step 1:

5000

10% of 5000=500

5% of 5000=250

25%=500+500+250= 1250 rupees

so...

5000-1250= 3750 INR, which is the original price, <u>BEFORE THE 25% WAS ADDED</u>

but..

They only want a 10% discount of the price which is 25% above the cost (5000). So essentially we want to find 15%, because 25%-10%=15%

so if...

10%=500

5%=250

15%=750 INR

this means the price with the 10% discount off 25%= 4250 INR (5000-750)

now we need to find the percentage change. For this we need to subtract the price with the 15% discount with the price BEFORE THE 25% was added

e.g 4250-3750= 500INR

Then.. divide this price with the original price before the 25% was added

e.g 500/3750= 2/15=0.13

So...

Convert 0.13 into a percentage=13%

The PERCENTAGE PROFIT of the owner is 13%

P.S Please could someone double check this answer as I am only 15 years old and may have gotten some working out wrong! Thank you

3 0

3 years ago