<em>Answer,</em>
<em><u>4a^3 − 10a + 6/3a^2</u></em>
<em>Explanation,</em>
<em><u>Just Simplify</u></em>
<em>= 16a^4 − 40a^2 + 24a/12a^3</em>
<em>= 16a^3 − 40a + 24/12a^2</em>
<em>= </em><em>4a^3 − 10a + 6/3a^2</em>
<u><em>Hope This Helps :-)</em></u>
Answer:
1.The sum of thrice a certain number and six is greater than twenty seven.
2. Three times a certain number added to six the result is greater than twenty seven.
Step-by-step explanation:
The inequality whose word problem to be written is 3x + 6 > 27
Let x be a certain number.
So, we can write the following as the word problem of the inequality :
1.The sum of thrice a certain number and six is greater than twenty seven.
2. Three times a certain number added to six the result is greater than twenty seven.
<span>The greatest number that has one comma when written with numerals and with number names is 999,999
In number names form is is written: nini hundred and ninety nine thousand, nine hundred and ninety nine.
</span>
Answer:
Step-by-step explanation:
The common difference (d) can be found using the first and 4th terms:
a1 = 3
a4 = a1 +d(4 -1)
-9 = 3 +3d . . . . . simplify
-3 = 1 + d . . . . . . divide by 3
-4 = d . . . . . . . . . subtract 1
Then ...
x = a1 + d = 3 -4 = -1
y = x + d = -1 -4 = -5
The values of x and y are -1 and -5, respectively.
It is the answer in pencil hope this helps it not tell me
