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3 years ago

What answer exercise 7b

Mathematics

1 answer:

Effectus [21]3 years ago

5 0

Answer:

the first box0.463..

the 2nd box 0.000566

the 3rd box0

the 4th box invalid operation

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What is 10×2/5 in unit form?

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10*2/5= 20/5 = 4 = 4.0 where 4 is the unit.(whole number)

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3 years ago

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Andre knows he wants a sandwich that has ham, lettuce, and tomatoes on it. He doesn’t care about the type of bread or cheese. Ho

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. He could easily make a ham sandwich, any Burger made with ham as well.

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3 years ago

Water flows through a pipe of diameter 4cms with a velocity of

MissTica

Answer:

1.28 m

Step-by-step explanation:

The speed at which water rises in the tank is proportional to the speed of the water in the pipe and inversely proportional to the ratio of the tank area to the pipe area.

The ratio of tank area to pipe area is the square of the ratio of their diameters:

((150 cm)/(4 cm))² = 1406.25

Then the rate of rise of water in the tank is ...

(0.5 m/s)/(1406.25)

After 1 hour = 3600 seconds, the height of the water will be ...

rise = (time)(rate of rise)

(3600 s)(0.5 m/s)/1406.25 = 1.28 m

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3 years ago

Simplify and find any restrictions<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B9x%7D%20-%5Cfrac%7B6%7D%7B2x%5E2%7D" i

Yuki888 [10]

Simplified: $\frac{4}{9x} -\frac{3}{x^{2} }$

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3 years ago

The number of electrical outages in a city varies from day to day. Assume that the number of electrical outages ( x ) in the cit

forsale [732]

Answer:

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

Step-by-step explanation:

Given the probability distribution table below:

$\left|\begin{array}{c|cccc}x&0&1&2&3\\P(x)&0.8&0.15&0.04&0.01\end{array}\right|$

(a)Mean

Expected Value, $\mu =\sum x_iP(x_i)$

=(0*0.8)+(1*0.15)+(2*0.04)+(3*0.01)

=0+0.15+0.08+0.03

Mean=0.26

(b)Standard Deviation

$(x-\mu)^2\\(0-0.26)^2=0.0676\\(1-0.26)^2=0.5476\\(2-0.26)^2=3.0276\\(3-0.26)^2=7.5076$

Standard Deviation $=\sqrt{\sum (x-\mu)^2P(x)}$

$=\sqrt{0.0676*0.8+0.5476*0.15+3.0276*0.04+7.5076*0.01}\\=\sqrt{0.3324}\\=0.5765$

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

3 0

3 years ago

What answer exercise 7b​

What answer exercise 7b