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seropon [69]
3 years ago
9

What is the length of side s of the square shown below?

Mathematics
1 answer:
Tomtit [17]3 years ago
7 0
Maybe take a picture of it?
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What number is 15% of 63
Degger [83]
Take the number (63) and then divide it with 100, this gives you 1%. Then you want to multiply with with 15 in order to get 15%. The answer becomes:

\frac{63}{100}\cdot 15=9.45
6 0
3 years ago
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Trail mix made for three people uses 3 cups of almonds, 1 cup of raisins and 1/3 cup of chocolate chips. If the same ratio of in
kvv77 [185]
Hello!

Since this amount we are given an amount we need for 3 people, we just multiply each amount by four to get to 12.

12 cups of almonds
4 cups of raisins
1 1/3 cups of chocolate chips

I hope this helps!
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3 years ago
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If the class started at 11:30 A.M. and ended at 12:25 P.M., how long did the class last?
Delicious77 [7]

Answer: 55 minutes

Step-by-step explanation:

If the class started at 11:30 A.M. and ended at 12:25 P.M., how long did the class last? 55 minutes

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3 0
3 years ago
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What else would need to be congruent to show that ABC = XYZ by ASA
andre [41]

Answer: Choice C.

Explanation: ASA stands for "angle side angle". To use ASA, we must have two pairs of congruent angles, as well as a pair of congruent sides. The sides must be between the angles in question

7 0
3 years ago
Find the area of this regular polygon.<br> Round to the nearest tenth.<br> 8.65 mm<br> [? ]mm2
nadezda [96]

Answer:

Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:

a=√{b²+c²−2bc×cos40°}

a=√{149.645−149.645cos40°}

Area Nonagon = (9/4)a²cos40°

=9/4[149.645−149.645cos40°]cot20°

=336.70125[1−cos(40°)]cot(20°)

Applying an identity for the cos(40°) does not get us very far…

= 336.70125[1−(cos2(20°)−1)]cot(20°)

= 336.70125[2−cos2(20°)]cot(20°)

= 336.70125[2−(1−sin2(20°))]cot(20°)

= 336.70125[1+sin2(20°)]cos(20°)sin(20°)

= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²

3 0
3 years ago
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