First to get the equation you knew to understand one thing about perpendicular lines. The slope of the line is the opposite reciprocal of the perpendicular lines or the new slope is m = 10.
Then you use the formula
y = mx + b
you plug in your values from the point and the new slope.
(1,5) with new slope m
5= 10(1)+b
5-10=b
-5 = b
then make your new equation
y = 10x -5
that's your line that goes through point (1,5) and is perpendicular to the line given
Given, (0,−2).
Since the x-coordinate is 0, the point clearly lies on y-axis.
Also, the y-coordinate −2 being negative, the point lies on the negative y-axis.
As it stands, it's none of those. I believe you were going for the distance formula but copied it wrong.
Answer:
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Step-by-step explanation:
