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Reil [10]
3 years ago
10

Find the perimeter pf a rectangular parking lot that has a width of 3x+2 and a length of 5x-7.*

Mathematics
1 answer:
uranmaximum [27]3 years ago
8 0

Answer:

<u>Perimeter</u><u> </u><u>is</u><u> </u><u>1</u><u>6</u><u>x</u><u> </u><u>-</u><u> </u><u>1</u><u>0</u>

Step-by-step explanation:

{ \sf{perimeter = 2(length + width)}} \\ p = 2 \{(5x - 7) + (3x + 2) \} \\ p = 2(8x - 5) \\ p = 16x - 10

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A data set consists of 2, 2, 3, 4, 5, 5, and 7. Then, 20 is added to the data set. The new value will have little effect on the
ale4655 [162]

Answer:

A data set consists of 2,2,3,4,5,5 and 7. Then, 20 is added to the data set. The new value will have the little effect on the median, but it will raise the mean significantly.

Step-by-step explanation:

Since, we all know that the measures of central tendency are:

  1. Arithmetic Mean
  2. Median
  3. Mode
  4. Geometric Mean
  5. Harmonic Mean

Let us define Arithmetic Mean and Median.

Arithmetic mean is the sum of observations divided by the total number of observations. It is denoted by (x bar).

On the other hand, median of a distribution is that value of the variable which divides it into two equal parts.

For Arithmetic Mean:

According to the question, when data set consists 2,2,3,4,5,5 and 7, the arithmetic mean for the given data = 4

After adding 20 the given data set, the mean will be = 6

For median:

When data set consists of 2,2,3,4,5,5 and 7, the median value will be the middle value of the distribution i.e. = 4

After adding 20 to the given data set, the median will be = 4.5

Here we can say that 20 is an outlier for the given data set.

Since mean has the significant effect of the outlier because it is based on all values but the median has lesser effects of the outlier as it is based only on middle values. So whatever outlier is added to median, it will not show particular changes.

Thus , a data set consists of 2,2,3,4,5,5 and 7. Then, 20 is added to the data set. The new value will have little effect on median, but it will raise the mean significantly.

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Step-by-step explanation:

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