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Kay [80]
3 years ago
8

Please help with this, its do right know

Mathematics
2 answers:
emmainna [20.7K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

y = 3x + 10

Ur welcome

Olin [163]3 years ago
3 0
The answer is A because it can be put into the equation: y= 3x+10
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I need both of these answered
olga_2 [115]
Q18)
7/0.75 = 28/3
28/3(45) = 420 -> 420/60 = 7
Therefore the answer is B. 7 minutes.
Q20)
60.90/5 = 12.18
12.18(7) = 85.26
85.26+14.99 = 100.25
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6 0
2 years ago
An aircraft has a total time in service of 468 hours. The Airworthiness Directive given was initially complied with at 454 hours
Georgia [21]

Answer:

440 hours

Step-by-step explanation:

In this case the aircraft has completed one cycle of service in the first 454 hours of service. Then making the difference between the hours of service and the hours of the first cycle we have:

Hours of the second cycle= Total time in service- time Airworthiness Directive

=468-454=14

Then we have 14 hours of service and need to accumulate the rest to complete 454. It is

454-14=440

Then we need to accumulate 440 hours additional to complete the Airworthiness Directive .

6 0
3 years ago
Triangles 1 and 2 have the angle measures
lawyer [7]

Answer:

C

Step-by-step explanation:

Both triangles have three angles of the same value.

Remember that the angles in all triangles add up to 180°.

Let's use that to find out the unknown angles.

For the first triangle:

180 - 82 - 43 = 55°

55° is also in the second triangle.

Let's check with the second triangle:

180 - 82 - 55 = 43°

43° is also in the first triangle.

Therefore, both triangles are similar as the angles in both triangles are the same - 82°, 43° and 55°.

Hence, C.

7 0
3 years ago
Solve the system by elimination
andreev551 [17]
The answer is x=5 and y=-2

3 0
3 years ago
Number 2 I need help on how to solve it
Hunter-Best [27]

Let's simplify the following expression:

\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}

We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

4 0
1 year ago
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