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Klio2033 [76]
3 years ago
8

PLEASE ANSWER QUICKLY ASAP READ THE QUESTION CAREFULLY PLEASE ​

Mathematics
2 answers:
Anna11 [10]3 years ago
6 0

Answer:

140°

Step-by-step explanation:

total angle of a hexagon is 720. We know already 510°. That leaves 210°. The ratio between the two angles is 2:1, therefore angle CDE is 140° and angle DEF is 70 °

AURORKA [14]3 years ago
4 0

Answer:

140°

Step-by-step explanation:

We know that all of these angles here are part of a hexagon, meaning that their angle measures will all add up to 720°.

We can use what we already know and find what CDE and DEF will add up to.

145+90+160+115=510\\720-510=210

Now, assuming x is the measure of DEF, we can create an equation for this.

x + 2x = 210\\3x = 210\\x = 70

This is the measure of DEF, but it asks for CDE, which is twice the size of DEF. So

70\cdot2=140

We can double check this is right by adding up all the measures.

145+90+160+115+140+70=720

Hope this helped!

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Read 2 more answers
While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at
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The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) =  speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s

23/(2.8 + x)+ 23 / (2.8-x) = 29

LCD = (2.8 + x)(2.8 - x)

23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)

simplifying the equation, we get

23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)

23(2.8+2.8)/29=2.8^2-x^2

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x=\sqrt{3.4}=1.84m/s

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The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

To learn more about Speed refer to:

brainly.com/question/4931057

#SPJ4

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