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geniusboy [140]
3 years ago
10

What is the slope of y = -4

Mathematics
1 answer:
atroni [7]3 years ago
5 0

Answer:

the slope is zero because the slope is zero

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14. The diagonals of square ABCD intersect at E. If AE = 2, find the perimeter of ABCD.
lutik1710 [3]

Answer:

B, 8\sqrt{2}

Step-by-step explanation:

Diagonals of a square are congruent so AC= 4

using pythagorean theorem we can then do x^{2} +x^{2}=4^{2}

2x^{2} = 16\\x^{2} =8\\x=\sqrt{8} \\x=2\sqrt{2}

Then for perimeter we times the 2\sqrt{2} by 4 and get

8\sqrt{2}

Hope this helps and please mark brainliest!!

8 0
3 years ago
HELP PLS I NEED IN 5 MINUTES
Westkost [7]

Answer:

x = 8

Step-by-step explanation:

Triangle OBC is congruent to triangle OBA (SAS  ----  side angle side)

5 0
3 years ago
What are one dimensional figures
agasfer [191]
Hello!

In geometry there are three dimensions.

Something that is one dimensional is neither flat, wide, or tall. It is just a line.
——————————————
Something two dimensional is flat and wide but has no height. An example of this is a square.

Something three dimensional is wide and tall, and has flat faces. An example is a cube.

To answer your question something one dimensional is something that is not flat, wide, or tall, such as a line.

Hope this helped!
3 0
3 years ago
How to write 30 1/4% as a fraction in simplest formq
ycow [4]
p\%=\dfrac{p}{100}\\\\30\dfrac{1}{4}=\dfrac{30\cdot4+1}{4}=\dfrac{121}{4}\\\\30\dfrac{1}{4}\%=\dfrac{121}{4}\%=\dfrac{\frac{121}{4}}{100}=\dfrac{121}{4}\cdot\dfrac{1}{100}=\dfrac{121}{400}\\\\Answer:\boxed{30\frac{1}{4}\%=\frac{121}{400}}
8 0
3 years ago
Giving brainliest! Please show the working out
tiny-mole [99]

Answer:

see explanation

Step-by-step explanation:

(a)

OC = OB ( both radii of the circle )

Thus Δ BOC is isosceles with congruent base angles.

∠ BOC = ∠ BCO = 50°

(b)

∠ ACB = 90° ( angle in a semicircle ), then

∠ ACO = 90° - 50° = 40°

OA = OC ( both radii of the circle )

Thus Δ ACO is isosceles with congruent base angles.

∠ BAC = ∠ ACO = 40°

7 0
3 years ago
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