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adell [148]
3 years ago
11

A recipe calls for 2/5 cup of chicken broth and 1/6 cup of vegetable broth. What is the total amount of broth need for the recip

e?​
Mathematics
1 answer:
Bess [88]3 years ago
3 0

Answer:

I may not be correct, depending on what you were taught, but it would be...

17/30

Step-by-step explanation:

(2/5×6/6)+(1/6×5/5)

12/30 + 5/30

17/30

keep in mind you don't add the denominators at all ( the numbers at the bottom half of the fraction)

You might be interested in
Can a triangle have sides with the given lengths? <br> 2 in, 4 in, 6 in
Zanzabum

Answer:

NO

Step-by-step explanation:

Because the sum of the minor sides equals the measure of the major side, it must be less.

2 + 4 = 6

Hope this helps

6 0
2 years ago
The mean of the masses of five articles is 215 g. When another article is added, the mean of the masses of the six articles is 2
lbvjy [14]

Mass of the sixth article will be :

\boxed{ \boxed{245 \: g}}

\mathrm{✌TeeNForeveR✌}

4 0
3 years ago
Answer the 3 questions PLEASE
liberstina [14]
8. it’s skewed right
9. The spread is 21 to 100
10.the center is 80 or 81
3 0
3 years ago
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                     = 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0
3 years ago
What is the quotient of 5/6 divided by 3/4
matrenka [14]
The correct answer is 10/9 or 1.1. Hope this helps.
8 0
3 years ago
Read 2 more answers
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