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Sati [7]
3 years ago
6

Please help me with this

Mathematics
1 answer:
eduard3 years ago
4 0

Answer:

x = -3/2 or x= sqareroot41/2

Step-by-step explanation:

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If sin^-1 (x+3) = -pi/6 , x = ?
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First recall that \sin^{-1}x is defined only for -1\le x\le1, which means \sin^{-1}(x+3) requires that 2\le x+3\le4.

Over this domain, \sin^{-1}(x+3) will be invertible, and so taking the sine of both sides, we have

\sin^{-1}(x+3)=-\dfrac\pi6\implies\sin\left(\sin^{-1}(x+3)\right)=\sin\left(-\dfrac\pi6\right)
x+3=-\sin\dfrac\pi6
x+3=-\dfrac12
x=-\dfrac72
7 0
3 years ago
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maxonik [38]

Answer:

-12, -11, 4, 12

Step-by-step explanation:

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2 years ago
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Ksju [112]

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(x-12) (x+12)

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9 0
3 years ago
5x + 3<br> ----------<br> 15 <br><br><br> How is this solved?
Bas_tet [7]
This expression can't be simplified any further be as there is no common factor for the numerator and the denominator.
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Lelechka [254]
16x.30=4.80
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