About 1.6 miles.
You divide the 4 by 30 to get the distance per minute and multiply it by 12.
You need to use the cosine for this and this is how you do it.
Answer: B. No
Step-by-step explanation:
Direct variation has the following form:

Where the constant of variation is "k".
By definition, in direct variation, when the variable "x" changes, tha variable "y" changes in proportion to the variable "x".
As you can observe in the table, when the value of the variable "x" increase, the values of the variable "y" decrease, therefore we can conclude that it is not a direct variation.
Then the answer is the option B.
Answer:
i worked out the equation provided and all i get is (y = -2.5)
Step-by-step explanation:
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Write the expression below in terms of x and y only:
(I'm going to call it "E")
![\mathsf{E=sin\!\left[sin^{-1}(x)+cos^{-1}(y)\right]\qquad\quad(i)}](https://tex.z-dn.net/?f=%5Cmathsf%7BE%3Dsin%5C%21%5Cleft%5Bsin%5E%7B-1%7D%28x%29%2Bcos%5E%7B-1%7D%28y%29%5Cright%5D%5Cqquad%5Cquad%28i%29%7D)
Let

so the expression becomes

• Finding

![\mathsf{sin\,\alpha=sin\!\left[sin^{-1}(x)\right]}\\\\ \mathsf{sin\,\alpha=x\qquad\quad\checkmark}](https://tex.z-dn.net/?f=%5Cmathsf%7Bsin%5C%2C%5Calpha%3Dsin%5C%21%5Cleft%5Bsin%5E%7B-1%7D%28x%29%5Cright%5D%7D%5C%5C%5C%5C%20%5Cmathsf%7Bsin%5C%2C%5Calpha%3Dx%5Cqquad%5Cquad%5Ccheckmark%7D)
• Finding


because

is positive for
![\mathsf{\alpha\in \left[-\frac{\pi}{2},\,\frac{\pi}{2}\right].}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Calpha%5Cin%20%5Cleft%5B-%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%5C%2C%5Cfrac%7B%5Cpi%7D%7B2%7D%5Cright%5D.%7D)
• Finding

![\mathsf{cos\,\beta=cos\!\left[cos^{-1}(y)\right]}\\\\ \mathsf{cos\,\beta=y\qquad\quad\checkmark}](https://tex.z-dn.net/?f=%5Cmathsf%7Bcos%5C%2C%5Cbeta%3Dcos%5C%21%5Cleft%5Bcos%5E%7B-1%7D%28y%29%5Cright%5D%7D%5C%5C%5C%5C%20%5Cmathsf%7Bcos%5C%2C%5Cbeta%3Dy%5Cqquad%5Cquad%5Ccheckmark%7D)
• Finding


because

is positive for
![\mathsf{\beta\in [0,\,\pi].}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cbeta%5Cin%20%5B0%2C%5C%2C%5Cpi%5D.%7D)
Finally, you get
![\mathsf{E=x\cdot y +\sqrt{1-y^2}\cdot \sqrt{1-x^2}}\\\\\\ \therefore~~\mathsf{sin\!\left[sin^{-1}(x)+cos^{-1}(y)\right]=x\cdot y +\sqrt{1-y^2}\cdot \sqrt{1-x^2}\qquad\quad\checkmark}](https://tex.z-dn.net/?f=%5Cmathsf%7BE%3Dx%5Ccdot%20y%20%2B%5Csqrt%7B1-y%5E2%7D%5Ccdot%20%5Csqrt%7B1-x%5E2%7D%7D%5C%5C%5C%5C%5C%5C%20%5Ctherefore~~%5Cmathsf%7Bsin%5C%21%5Cleft%5Bsin%5E%7B-1%7D%28x%29%2Bcos%5E%7B-1%7D%28y%29%5Cright%5D%3Dx%5Ccdot%20y%20%2B%5Csqrt%7B1-y%5E2%7D%5Ccdot%20%5Csqrt%7B1-x%5E2%7D%5Cqquad%5Cquad%5Ccheckmark%7D)
I hope this helps. =)
Tags: <em>inverse trigonometric trig function sine cosine sin cos arcsin arccos sum angles trigonometry</em>