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stepladder [879]

2 years ago

10

Yesterday, there were 56 problems assigned for math homework. Desmond got 14 problems correct and 42 problems incorrect. What pe

rcentage did Desmond get correct?

1 answer:

Vika [28.1K]2 years ago

6 0

Answer: 25%

100/56 = 1.785714285714286

1.785714285714286 x 14 = 25

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Which information is not necessary to solve this problem? WHO EVER GETS THIS FIRST IS BRAINLIEST

Ad libitum [116K]

So we need to now how many crates they sold, how many boxes are in a crate, and how much they sold the cates for.

So we don't need A. we don't need to know how much is in the box, just how much money they made from the box.

4 0

3 years ago

A total of 285 tickets were sold for the school play. they were either adult tickets or student tickets. the number of student t

Assoli18 [71]

Lets say the number of adult tickets is x. This means the number of student tickets is 2x. So, 2x + x = 285, or 3x =285. The means x = 95. So the number of adult tickets sold is 95.

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3 years ago

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5 0

3 years ago

Read 2 more answers

A Web music store offers two versions of a popular song. The size of the standard version is 2.8 megabytes (MB). The size of the

Serga [27]

Answer:

Number of high quality version downloads = 880

Step-by-step explanation:

Let,

x be the number of standard version songs downloaded

y be the number of high quality version songs downloaded

According to given statement,

x+y=1600 Eqn 1

2.8x+4.1y=5624 Eqn 2

Multiplying Eqn 1 by 2.8 to eliminate x

2.8(x+y=1600)

2.8x+2.8y=4480 Eqn 3

Subtracting Eqn 3 from Eqn 2

(2.8x+4.1y)-(2.8x+2.8y)=5624-4480

2.8x+4.1y-2.8x-2.8y=1144

1.3y=1144

Dividing both sides by 1.3

$\frac{1.3y}{1.3}=\frac{1144}{1.3}\\y=880$

Hence,

Number of high quality version downloads = 880

3 0

3 years ago

Suppose you invest $150 a month for 5 years into an account earning 7% compounded monthly. After 5 years, you leave the money, w

lisabon 2012 [21]

Answer:

About 0.3 billion dollars

Step-by-step explanation:

5 years = 60 months.

The 150 of the first month will be 150*1.07^60 in 5 years.

The 150 of the second month will be 150*1.07^59 in 5 years.

The 150 of the third month will be 150*1.07^58 in 5 years.

And so forth.

So we sum that up:

( sum_(n=1)^(60) 150×1.07^n)

And multiply with

× 1.07^(5×23)

to account for the increase in value in the following 23 years.

7 0

2 years ago