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deff fn [24]
2 years ago
9

Plzzzzz help meee!!!!!!!!!!!!

Mathematics
2 answers:
eimsori [14]2 years ago
8 0

Answer:

The believe the function is 3.

Greeley [361]2 years ago
8 0

Answer:

since there is one value of Y for every value of X its a function

Step-by-step explanation: like all of its a function

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You get a 15% raise at your job and now make $13.50 per hour. What was you previous rate of pay per hour?
Anestetic [448]
<h2>We know:</h2>

You currently make $13.50 an hour. You've earned a 15% pay raise. You want to find out your previous rate of pay per hour.


<h2>Steps:</h2>

1.) Convert 15% to a decimal, which equals 0.15


2.) Multiply your current earnings with the percentage in decimal form (0.15)

$13.50 (current pay per hour) x 0.15 (percentage in decimal form) = $2.025 (difference between your previous wage and your current wage)


3.) Subtract the difference of your previous wage and current wage with your current earnings

$13.50 (current pay per hour) - $2.025 (difference between previous and current wage) = $11.475 (previous pay per hour)


4.) Since this is talking about wage, rounding is not applicable. In other cases, your number would be rounded off to $11.48, however you can't add what you don't have, so you would have to round down.


<h2>You were previously making $11.47 an hour.</h2>
7 0
3 years ago
You are most likely to encounter an irrational numbers when you’re
MArishka [77]

Answer:

Taking square-root of numbers

Step-by-step explanation:

The reason is that the square-root of most numbers is an irrational number because the answer we have can not be written as p/q form. For example, if we take the example of √2 then the answer we have is "1.4142135623730950..." which can not be written in p/q form. Hence taking square-root of numbers will most likely give an irrational number.

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3 years ago
HELP PLEASE! FIND THE SURFACE AREA OF PYRAMID
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Answer:

136.73972

Step-by-step explanation:

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2)2+92+5.2·(6

2)2+92≈136.73972

6 0
3 years ago
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Match the English word or phrase to its math equivalent.
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