<u>Answer:</u>
The expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour
<u>Solution:</u>
Given that,
Distance covered by an elephant in 36 seconds is equal to 1 mile
Therefore, <em>distance covered by the elephant in 1 second</em> is 
mile
Therefore, <em>distance covered by the elephant in 60 seconds</em> (60 seconds = 1 minute) is
Therefore, <em>distance covered by the elephant in 60 minute</em> (60 minute = 1 hour) is
Hence the expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour
Answer:
x = -1
Step-by-step explanation:
1/4 (4x - 4) = -2(6x + 7)
1x - 1 = -12x - 14
13x = -13
x = -1
180- 113 = 67
180- 67= 113
<5= 67
<2=113
Answer:
Step-by-step explanation:
Given:
elongation, x = 0.50 in
Force, f = 9000 lb
Young modulus, E = 10,000,000 psi
Maximum Stress, Sm = 30000 psi
Length, L = 16 ft
Converting ft to in,
12 in = 1 ft
=16 × 12 = 192 in
Young modulus, E = stress/strain
Stress = force/area, A
Strain = elongation, x/Length, L
E = f × L/A × E
1 × 10^7 = stress/(0.5/16)
= 26041.7 psi
Minimum stress = 26041.7 psi
Maximum stress = 30,000 psi
Stress = force/area
Area = 9000/26041.7
= 0.3456 in^2
Stress = force/area
Area = 9000/30000
= 0.3 in^2
Using minimum area of 0.3 in^2,
A = (pi/4)(d^2)
0.3 in^2 = (pi/4)(d^2)
d = 0.618 inches
diameter, d = 0.618 inches
Answer:
3 7/12
Step-by-step explanation:
There are 12 inches in 1 feet. So 43 inches would be 43/12=3 7/12 feet.
