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JulsSmile [24]
3 years ago
5

Michiko bought pens for $3.85 and pencils for $1.25 how much did she spend all together? ​

Mathematics
1 answer:
seropon [69]3 years ago
3 0

Answer:

5.1 :)

Step-by-step explanation:

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A businessman buys 1,440 dozen pens at $2.50 a dozen and then sells them at a price of 25¢ apiece. what is his total profit on th
Harlamova29_29 [7]
Profit (P) is calculated by subtracting the total cost (C) from the total revenue (R). The calculations are shown below, 

       R = (1440 dozens) x (12 pieces / 1 dozen) x (25 cents/ piece) = $4320
                   C = (1440 dozens) x ($2.50 / dozen) = $3600
 
                          Profit = R - C = $4320 - $3600 = $720

Thus, the businessman's profit is $720. 

7 0
3 years ago
PLEASEEEE HELP I WILL GIVE BRAINLIEST!!
I am Lyosha [343]

Answer:

The average is 5.41666667 degrees.

Step-by-step explanation:

3 0
3 years ago
Find x and y part 4 for these problems​
Dvinal [7]

Answer:

Step-by-step explanation:

3) Sin30 = 11/x

x = 11/Sin30 = 11/0.5

x = 22

Tan 30 = 11/y

y = 11/tan30 = 11/0.5774

y = 19.1

4) Sin30 = 6/x

x = 6/Sin30 = 6/0.5

x = 12

Tan 30 = 6/y

y = 6/tan30 = 6/0.5774

y = 10.39

5) Sin45 = 9√2/y

y = 9√2/Sin45 = 9√2/(√2/2) =

9√2 × 2/√2 = 18

x = 18

Tan 45 = 9√2/x

x = 9√2/Tan 45 = 9√2/1

x = 9√2

6)

Sin60 = 9/x

x = 9/Sin60 = 9/0.866

x = 10.39

Tan 60 = 9/y/2 = 18/y

1.7321 = 18/y

y = 18/1.7321

y = 10.39

6 0
3 years ago
Add and simplify 9 sixteenths plus one half equals
brilliants [131]
9/16 + 1/2 = 9/16 + 8/16 = 17/16 = 1 1/16
5 0
3 years ago
Calculate the area of the regular pentagon below: A regular pentagon with side length of 11.8 inches and dotted line from center
vlada-n [284]

Answer:

Area of regular pentagon is 238.95 square inches.

Step-by-step explanation:

Given a regular pentagon with side length of 11.8 inches and dotted line from center to middle of side of 8.1 inches.

we know a regular polygon divides into 5 congruent triangles.

Side of pentagon i.e base of one triangle is 11.8 inches.

Also, distance from center to middle of side which is height of triangle is 8.1 inches.

Area of 1 triangle= \frac{1}{2}\times base\times height

                           =  \frac{1}{2}\times 11.8\times 8.1

                           = 47.79 sq inches.

Area of regular pentagon=area of 5 congruent triangles= 5\times 47.79=238.95 sq inches.

5 0
3 years ago
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