Answer:
% Po lost = 100[1 - e^(-0.005t)] %; 73.0 g
Step-by-step explanation:
p(t) = 100e^(-0.005t)
Initial amount: p(0) = 100
Amount remaining: p(t) = 100e^(-0.005t)
Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]
% of Po lost = amount lost/initial amount × 100 %
= [1 - e^(-0.005t)] × 100 % = 100[1 - e^(-0.005t)] %
p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g
The mass of polonium remaining after 63 days is 73 g.
Answer:
Question:14
3x4 (for the left square, 3 on the side(width) and 4 on the bottom(length))
3x9 (for the right square, 3 on the side(width) and 4 on the bottom(length))
3x13 (for the entire rectangle)
Question:15
3x10 (for the left, 3 on the side(width) and 10 on the bottom(length))
3x6 (for the right, 3 on the side(width) and 6 on the bottom(length))
Step-by-step explanation:
The answer is the 3rd one
