There are 440 thousands :)
Simplfy then combine like terms so the anwser Simplified and Evaluated is -17x-19
You want to draw 2 kings from a 52 card deck. And you do it with replacement.
There are 4 kings in a standard deck. The probability of getting one of them is
4/52 on the first draw.
For the second draw the probability is the same.
4/52
The probability for both happening is
(4/52)*(4/52) = (1/13)*(1/13) = 1/169 = 0.001597
Answer:
Hope the pictures will help you..
Assuming the order required is as n-> inf.
As n->inf, o(log(n+1)) -> o(log(n)) since the 1 is insignificant compared with n.
We can similarly drop the "1" as n-> inf, the expression becomes log(n^2+1) ->
log(n^2)=2log(n) which is still o(log(n)).
So yes, both are o(log(n)).
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