All categories

3 years ago

A and B are independent events. P(A) = 0.80 and P(B) = 0.10. What is P(A and B)?

Mathematics

2 answers:

Mandarinka [93]3 years ago

7 0

Answer:

C 0.90

Step-by-step explanation:

Add 0.10 and 0.80=0.90

Anuta_ua [19.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

P(A and B)=P(A)×P(B)=0.80×0.10=0.08

You might be interested in

A marina is in the shape of a coordinate grid. Boat A is docked at (3.1, −1) and Boat B is docked at (−4.1, −1). The boats are _

kirill115 [55]

Answer:

d = 7.2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra II

Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Boat A(3.1, -1)

Boat B(-4.1, -1)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d.

Substitute [DF]: $d = \sqrt{(-4.1-3.1)^2+(-1+1)^2}$
Subtract/Add: $d = \sqrt{(-7.2)^2+(0)^2}$
Exponents: $d = \sqrt{51.84}$
Evaluate: $d = 7.2$

8 0

3 years ago

Read 2 more answers

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers

Find a fration or mixed number that is between -3 1/4 and -3 1/8

Alenkinab [10]

A fraction could be -3 1/6

8 0

3 years ago

A student simplified the expression 62122 as 12 Do you agree with this student

zhenek [66]

No because 62122 can not be simplified

6 0

3 years ago

3p^5 x 8p^3 / 2p , help? TvT

Sati [7]

Answer:

The expression 3p⁵ ₓ 8p³ / 2p can be simplified to 12p⁷.

Step-by-step explanation:

To simplify:

3p⁵ ₓ 8p³ / 2p

= (3 ₓ 8)(p⁵ ₓ p³) / 2p

= 24p⁸ / 2p

= 12p⁷

7 0

3 years ago