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Ilia_Sergeevich [38]
3 years ago
6

Find the slope of the line through each pair of points. (2, -4), (5,-8)

Mathematics
1 answer:
slega [8]3 years ago
8 0

Answer:

m=-\frac{4}{3}

Step-by-step explanation:

Slope=m=\frac{y_2-y_1}{x_2-x_1}

Here

(x_1, y_1)=(2, -4) \ \ and \ \  (x_2, y_2)=(5, -8)

m=\frac{-8-(-4)}{5-2}

m=-\frac{4}{3}

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8 0
3 years ago
In science class, Priscilla heats water and measures the temperature of the water every 2 minutes\or data are shown in the table
Dima020 [189]

Answer:

  37.5 °C

Step-by-step explanation:

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3 years ago
Here is a simple probability model for multiple-choice tests. Suppose that each student has probability p of correctly answering
Alla [95]

Answer:

a) The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

Step-by-step explanation:

a) To approximate this distribution we have to calculate the mean and the standard distribution.

The mean is the proportion p=0.85.

The standard deviation can be calculates as:

\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{100} }=0.04

To calculate the probability that Jodi scores 78% or less on a 100-question test, we first calculate the z-value:

z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.04} =-1.75

The probability for this value of z is

P(x

The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) In this case, the number of questions is 250, so the standard deviation needs to be calculated again:

\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{250} }=0.02

To calculate the probability that Jodi scores 78% or less on a 250-question test, we first calculate the z-value:

z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.02} =-3.5

The probability for this value of z is

P(x

The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

6 0
2 years ago
Match the solid figure to the appropriate formula.
AlekseyPX

1. L \cdot A=\pi r l        -       Cone

2. V=\frac{4}{3} \pi r^{3}         -        Sphere

3. T \cdot A=2 \pi r h+2 \pi r^{2} - Cylinder

4. V=\frac{1}{3} B h         -        Pyramid

5. L . A=p h         -        Prism

Solution:

1. L \cdot A=\pi r l

Lateral surface area of cone = \pi r l

where r is the radius of the cone and l is the slant height of the cone.

2. V=\frac{4}{3} \pi r^{3}

Volume of sphere = \frac{4}{3} \pi r^{3}

where r is the radius of the sphere.

3. T \cdot A=2 \pi r h+2 \pi r^{2}

Total surface area of cylinder = 2 \pi r h+2 \pi r^{2}

where r is the radius of the cylinder and h is the height of the cylinder.

4. V=\frac{1}{3} B h

Volume of pyramid = \frac{1}{3} B h

where B is the base area of the pyramid and h is the height of the pyramid.

5. L . A=p h

Lateral surface area of prism = p h

where p is the perimeter of the base and h is the height of the prism.

4 0
3 years ago
Find the slope of the line passing through the points (-6,2), (0,-6).
Serhud [2]

C. -4/3

slope =  \frac{(y _{2} - y _{1}) }{(x _{2} - x _{1} )}  \\  =  \frac{( - 6 - 2)}{(0 -( -  6)}  \\  =  \frac{ - 8}{ 6}  \\  =   - \frac{4}{3}

3 0
3 years ago
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