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3 years ago

Find the slope of the line through each pair of points. (2, -4), (5,-8)

Mathematics

1 answer:

slega [8]3 years ago

8 0

Answer:

$m=-\frac{4}{3}$

Step-by-step explanation:

$Slope=m=\frac{y_2-y_1}{x_2-x_1}$

Here

$(x_1, y_1)=(2, -4) \ \ and \ \ (x_2, y_2)=(5, -8)$

$m=\frac{-8-(-4)}{5-2}$

$m=-\frac{4}{3}$

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How do you solve this equation . Q=3a+5ac

mr_godi [17]

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3 years ago

In science class, Priscilla heats water and measures the temperature of the water every 2 minutes\or data are shown in the table

Dima020 [189]

Answer:

37.5 °C

Step-by-step explanation:

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3 years ago

Here is a simple probability model for multiple-choice tests. Suppose that each student has probability p of correctly answering

Alla [95]

Answer:

a) The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

Step-by-step explanation:

a) To approximate this distribution we have to calculate the mean and the standard distribution.

The mean is the proportion p=0.85.

The standard deviation can be calculates as:

$\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{100} }=0.04$

To calculate the probability that Jodi scores 78% or less on a 100-question test, we first calculate the z-value:

$z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.04} =-1.75$

The probability for this value of z is

$P(x$

The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) In this case, the number of questions is 250, so the standard deviation needs to be calculated again:

$\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{250} }=0.02$

To calculate the probability that Jodi scores 78% or less on a 250-question test, we first calculate the z-value:

$z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.02} =-3.5$

The probability for this value of z is

$P(x$

The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

6 0

2 years ago

Match the solid figure to the appropriate formula.

AlekseyPX

1. $L \cdot A=\pi r l$ - Cone

2. $V=\frac{4}{3} \pi r^{3}$ - Sphere

3. $T \cdot A=2 \pi r h+2 \pi r^{2}$ - Cylinder

4. $V=\frac{1}{3} B h$ - Pyramid

5. $L . A=p h$ - Prism

Solution:

1. $L \cdot A=\pi r l$

Lateral surface area of cone = $\pi r l$

where r is the radius of the cone and l is the slant height of the cone.

2. $V=\frac{4}{3} \pi r^{3}$

Volume of sphere = $\frac{4}{3} \pi r^{3}$

where r is the radius of the sphere.

3. $T \cdot A=2 \pi r h+2 \pi r^{2}$

Total surface area of cylinder = $2 \pi r h+2 \pi r^{2}$

where r is the radius of the cylinder and h is the height of the cylinder.

4. $V=\frac{1}{3} B h$

Volume of pyramid = $\frac{1}{3} B h$

where B is the base area of the pyramid and h is the height of the pyramid.

5. $L . A=p h$

Lateral surface area of prism = $p h$

where p is the perimeter of the base and h is the height of the prism.

4 0

3 years ago

Find the slope of the line passing through the points (-6,2), (0,-6).

Serhud [2]

C. -4/3

$slope = \frac{(y _{2} - y _{1}) }{(x _{2} - x _{1} )} \\ = \frac{( - 6 - 2)}{(0 -( - 6)} \\ = \frac{ - 8}{ 6} \\ = - \frac{4}{3}$

3 0

3 years ago