Answer:
The surface area of the pyramid is 208 units²
Step-by-step explanation:
Luckily, since this is a square pyramid, we only need to find two numbers. These two numbers are the area of the base and the area of one triangular side. After we find them, we need to add them all together.
First, the base:
Since it's a square, we can just do 8 · 8 and get 64. Now we have one of the two needed numbers.
Second, one of the triangles:
To start, we multiply the base (8) by the height (9) giving us 72. After we divide that by 2, we have the area of the triangle, which is 36. Now we have the second number down. Now we can...
Finally, add them all together:
Now that we have the area of the base (64) and one of our triangles (36), we need to add them together. We add the base once and the triangle four times (because there are four triangles) to get the total surface area. Our expression looks like this:
64 + 36 + 36 + 36 + 36
After doing some simplifying, we get our final number, 208.
The surface area of the pyramid is 208 units²
Evaluate the Function the answer is 34
The answer is C) Step 3
Li forgot to multiply the two negatives in order to get positive 3/10. The answer should not be negative.
The right steps are:
-4/5 / 8/-3
Flip the second part to multiply:
-4/5 * -3/8
Multiply:
12/40
Simplify:
3/10
I hope this helps!
The picture in the attached figure
we know that
if m ∠DAB=23.5°
then
arc DB=23.5°------> by central angle
the answer isarc DB=23.5°
Answer:
<em>Set the function equal to 0</em>
Step-by-step explanation:
<u>Standard Form of the Quadratic Equation</u>
The form
is called the standard form of a quadratic equation. It can be clearly identified the terms of a second-degree polynomial equated to 0.
The equation is given in the form:
And we need to operate the expression to make it look like a standard form. The first logical step should be to set the function equal to 0 and then start to operate the resulting expression. It can be done by subtracting 8 on both sides of the equation:
Answer: Set the function equal to 0
