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Paraphin [41]
3 years ago
10

Find the two positive intergers that satisfy the given requirements. The difference of numbers is 90 and the larger number is th

ree times the smaller number​
Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer:

45

135

Step-by-step explanation:

x-y = 90

x = 3y

3y - y = 90

2y = 90

y = 45

x = 3×45 = 135

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Please help me with this homework
Vera_Pavlovna [14]

Answer:

linear

non-linear

Step-by-step explanation:

8 0
3 years ago
Which expression shows that the quotient
Harrizon [31]

Answer:

Option (2)

Step-by-step explanation:

Given expression is \frac{2}{(3x-1)} ÷ \frac{6}{6x-1}

We further simplify this expression,

\frac{2}{(3x-1)} ÷ \frac{6}{6x-1}

= \frac{2}{(3x-1)}\times \frac{6x-1}{6}

= \frac{6x-1}{3(3x-1)}

= \frac{6x-1}{(9x-3)}

Therefore, \frac{6x-1}{(9x-3)} will be the quotient of the given expression.

x\neq \frac{1}{3} and x\neq \frac{1}{6} for which the given expression is not defined.

Option (2) will be the answer.

6 0
3 years ago
Theorem: A line parallel to one side of a triangle divides the other two proportionately.
Kisachek [45]

Answer:

Segment BF = 16

Step-by-step explanation:

The given theorem states that a line parallel to one side of a triangle divides the other two sides proportionately

The given theorem is the Triangle Proportionality Theorem

According to the theorem, given that segment DE is parallel to segment BC, we have;

\dfrac{AD}{BD} = \dfrac{AE}{EC}

Therefore;

BD = \dfrac{AD}{\left(\dfrac{AE}{EC} \right) }  = AD \times \dfrac{EC}{AE}

Which gives;

BD = 6 \times \dfrac{18}{12}= 9

Similarly, given that EF is parallel to AB, we get;

\dfrac{AE}{EC} = \dfrac{BF}{FC}

Therefore;

BF = FC \times \dfrac{AE}{EC}

Which gives;

BF = 24 \times \dfrac{12}{18} = 16

Therefore, the statement that can be proved using the given theorem is segment BF = 16.

8 0
3 years ago
To the nearest tenth, find the perimeter of ABC with vertices A(-1,4), B(-2,1) and C(2,1). show your work
liubo4ka [24]

we have to firstly apply the distance formula to find the length of sides of the triangle

distance formula = \sqrt{(x_{2} -x_{1})^2 +(y_{2}- y_{1})^2}

So length AB = \sqrt{(-2-(-1))^2+(1-4)^2}= \sqrt{1 +9}=\sqrt{10}

BC= \sqrt{(2-(-2))^2+(1-1)^2}= \sqrt{16+0}=4

AC = \sqrt{(2-(-1))^2+ (1-4)^2}= \sqrt{9+9}=\sqrt{18}=3\sqrt{2}

Now perimeter = AB+BC+AC = \sqrt{10}+4+3\sqrt{2}

Plug in calculator

perimeter= 11.4 units

7 0
3 years ago
the point (- 7, 4) is reflected over the line x = - 3 . Then , the resulting point is reflected over the line y = x . Where is t
uysha [10]

Answer:

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Step-by-step explanation:

first reflect over x=-3

(-7,-10)

then reflect over y=x

(-10,-7)

6 0
3 years ago
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