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svetoff [14.1K]
3 years ago
13

Need helpp fastt plss will give brainliest to who is correct plss helpp

Mathematics
2 answers:
LenaWriter [7]3 years ago
5 0

Answer: First answer, 1/4 * 1/4 * 1/4 * 1/4

............

Lady bird [3.3K]3 years ago
3 0

Answer:

pretty sure its 1/4 x 1/4 x 1/4 x 1/4

Step-by-step explanation:

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There are 99 males and 121 females participating in a marathon. What percent of the participants are female?​
ioda

To do this, we first want to see how many participants there are in total by adding both males and females.

99+121=220

Now we know that there were 220 total participants, but only 121 were females.

This allows us to set up the fraction 121/220= the percent female.

\frac{121}{220} =0.55

or 55%

8 0
2 years ago
6.
sweet-ann [11.9K]

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Step-by-step explanation:

<h3><em>The Answer is B, This is the answer beacuse R and S is true. There are some methonds you can do to help you solve any questions like these in the future. I hope this well help.</em></h3>
3 0
2 years ago
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Draw and label a tape diagram to represent the following (choose two to do):
Aloiza [94]

Answer:

ask ur teacher

Step-by-step explanation:

6 0
2 years ago
There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student
Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0
3 years ago
Identify the solution(s) of the system of equations, if any.<br> -6x - 4y = 12<br> 12y = -18x - 36
UkoKoshka [18]
-6x - 4y = 12|\div 2\\&#10;12y = -18x - 36|\div 6\\\\&#10;-3x-2y=6\\&#10;2y=-3x-6\\\\&#10;-3x-2y=6\\&#10;-3x-2y=6

Both equations are equivalent, so there are infinitely many solutions.
5 0
3 years ago
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