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3 years ago

IF YOU GET THIS RIGHT YOU GET BRAINLIEST

Mathematics

2 answers:

Kryger [21]3 years ago

6 0

Answer:

Step-by-step explanation:

25 x 2 = 50. 10% of 70 equals 7. 50 + 7 = 57. 70 - 57 = 13.

Readme [11.4K]3 years ago

6 0

Cards given to her friend brad + cards sold online = cards givin

25+25=50

Amount of cards + cards givin = amount left

70-50=20

10% of 20=2

20-2=18

Tasha has 18 left

Hope this helps

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dybincka [34]

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Alisiya [41]

$\displaystyle\sum_{r=1}^nr(r+1)\cdots(r+p-1)$

When $n=1$ ,

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Meanwhile, you have on the right

$\dfrac{(1)(1+1)(1+2)\cdots(1+p-2)(1+p-1)(1+p)}{p+1}=(1)(1+1)(1+2)\cdots(p-1)(p)=p!$

so the equality holds for $n=1$ .

Assume it holds for $n=k$ , i.e. that

$\displaystyle\sum_{r=1}^kr(r+1)\cdots(r+p-1)=\frac{k(k+1)(k+2)\cdots(k+p-1)(k+p)}{p+1}$

Now for $n=k+1$ , you have

$\displaystyle\sum_{r=1}^{k+1}r(r+1)\cdots(r+p-1)=\sum_{r=1}^kr(r+1)\cdots(r+p-1)+(k+1)(k+2)\cdots(k+1+p-1)$
$=\displaystyle\frac{k(k+1)(k+2)\cdots(k+p-1)(k+p)}{p+1}+(k+1)(k+2)\cdots(k+1+p-2)(k+1+p-1)$
$=\displaystyle\frac{k(k+1)(k+2)\cdots(k+p-1)(k+p)}{p+1}+(k+1)(k+2)\cdots(k+p-1)(k+p)$
$=\left(\dfrac k{p+1}+1\right)(k+1)(k+2)\cdots(k+p-1)(k+p)$
$=\dfrac{k+p+1}{p+1}(k+1)(k+2)\cdots(k+p-1)(k+p)$
$=\dfrac{(k+1)(k+2)\cdots(k+p-1)(k+p)(k+p+1)}{p+1}$

as required.

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3 years ago

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LiRa [457]

Answer:

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Step-by-step explanation:

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Aleks04 [339]

Sorry if wrong but here I go
so basically
you need to find the scale factor so
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4 years ago