Csc a - sin a = cos a cot a
1/sin a - sin a = cos a (cos a / sin a)
(1 - sin^2 a)/sin a = cos^2 a/sin a
cos^2 a/sin a = cos^2 a/sin a
Therefore, the given equation is an identity.
Let the only force acting on the ball is the gravity (free-failing) and the ball was initially stationary
vo = 0
s = vot + 1/2 gt^2
s = 1/2 x 10 x (2.2) ^2 = 24.2 m
The volume of the cone is: A. 213 ft³.
<h3>Volume of a Cylinder and a Cone</h3>
- Volume of cylinder = πr²h.
- Volume of cone = ⅓πr²h.
Given:
radius and height of both the cylinder and the cone are equal.
Volume of Cylinder = 639 ft³
Therefore:
πr²h = ⅓πr²h
This means that volume of cone would be ⅓ of the volume of the cylinder.
Volume of cone = ⅓(639) = 213 ft³
Therefore, the volume of the cone is: A. 213 ft³.
Learn more about volume of cone on:
brainly.com/question/13677400
Answer:
x= - 1/35. I'm pretty sure this is right.
