All categories

1 year ago

2 √(5) - √(5) + 4 √(5) + √(3) simplify

Mathematics

1 answer:

konstantin123 [22]1 year ago

4 0

Step-by-step explanation:

2√5 -√5 +4√5 +√3

2-1+4√5 +√3

5√5 + √3

You might be interested in

A carpenter has a board 400 inches long and 10 inches wide. He makes 5 identical shelves with the board and still has a piece of

Sedaia [141]

THE 5 IDENTICAL SHELVES WOULD have to be 76 because if you take 400 - 20 (because that left over) you get 380/5 you get 76 and to check your work you do 5x76=380+20 you get 400 so 76 is you answer

3 0

3 years ago

Read 2 more answers

2/3*x+3/4=8 what is x

matrenka [14]

Answer: x=10 7/8

Step-by-step explanation:

Subtract 3/4 from both sides. Multiply both sides by 3. Divide both sides by 2 (basically just isolate x on one side of the equal sign).

7 0

3 years ago

PLZZZ HELP ME OUT THIS DUE RIGHT NOW AND I FREAKING OUT PLEASE HELP ME P.S YOU HAVE WRITE ANSWERS FOR ALL OF THEM

Veseljchak [2.6K]

1. Negative
Explanation: A negative minus a positive will be a negative
2. Negative
Explanation: If you use your order of operations a negative multiplied by a negative will be positive but since BxB would be greater than A it would be negative for example 2-8 would equal -6

6 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago

Is this communities property yes or no 9+8 8+9

lorasvet [3.4K]

Yes it is just like a+b = b+a

5 0

3 years ago