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mart [117]
2 years ago
14

1)

Mathematics
1 answer:
rjkz [21]2 years ago
5 0

Answer:

D) 3.0

Hope this helped

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CAN ANYONE PLS TELL ME THE BOTH
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A construction company plans to invest in a building project. There is a 30% chance that the company will lose $30,000, a 40% ch
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Answer: Option 'A' is correct.

Step-by-step explanation:

Since we have given that

30% chance that the company will lose $30000.

40% chance of a break even that there is no loss and no profit.

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As we know the formula for "Expectation":

So, Expected value will be

\frac{30}{100}\times (-30000)+\frac{40}{100}\times 0+\frac{30}{100}\times 60000\\\\=03\times (-30000)+0.4\times 0+0.3\times 60000\\\\=-9000+18000\\\\=\$9000

Expected value is $9000. So, the company should proceed with the project.

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f a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8%, can we use the Normal a
Troyanec [42]

Answer:

Probability of at least 50 obese individuals in our sample is 0.92364 .

Step-by-step explanation:

We are given that a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8% .

Let X = Number of obese individuals

Firstly, X ~ Binom(n=300,p=0.198)

For approximating binomial distribution into normal distribution, firstly we have to calculate \mu and \sigma^{2} .

Mean of Normal distribution, \mu = n * p = 300 * 0.198 = 59.4

Variance of Normal distribution,\sigma^{2} = n * p * (1-p) = 300 *0.198 *0.802 = 47.64

So, now X ~ N(\mu = 59.4 , \sigma^{2} = 47.64)

The standard normal z score distribution is given by;

                     Z = \frac{X-\mu}{\sigma} ~ N(0,1)

So, probability of at least 50 obese individuals in our sample = P(X >= 50)

  P(X >= 50) = P(X > 49.5)  {using continuity correction}

  P(X > 49.5) = P( \frac{X-\mu}{\sigma} > \frac{49.5 - 59.4}{6.9} ) = P(Z > -1.43) = P(Z < 1.43) = 0.92364

Therefore, required probability is 0.92364 .

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