Find the derivative of y=8ln(sin t+9)

1 answer:

6 0

$\bf y=8ln[sin(t+9)]\\\\
-----------------------------\\\\
\cfrac{dy}{dx}=8\cdot \cfrac{cos(t+9)\cdot 1}{sin(t+9)}\implies \cfrac{dy}{dx}=8cot(t+9)$

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