To find where on the hill the canonball lands
So 0.15x = 2 + 0.12x - 0.002x^2
Taking the LHS expression to the right and rearranging we have -0.002x^2 + 0.12x -
0.15x + 2 = 0.
So we have -0.002x^2 - 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x^2 + 0.03x -2 = 0.
This is a quadratic eqn with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25. The second solution y = 0.15 * 25 = 3.75
The distributive property: a(b + c) = ab + ac
(x - 3)(4x + 2) = (x)(4x + 2) + (-3)(4x + 2)
= (x)(4x) + (x)(2) + (-3)(4x) + (-3)(2) = 4x² + 2x - 12x - 6
<h3>= 4x² - 10x - 6</h3>
Answer:
x = 4
Step-by-step explanation:
given 2 chords intersecting inside a circle , then
the product of the parts of one chord is equal to the product of the parts of the other chord, that is
9 × 4x = 8(4x + 2)
36x = 32x + 16 ( subtract 32x from both sides )
4x = 16 ( divide both sides by 4 )
x = 4
