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LiRa [457]
2 years ago
7

Diane has 496 beads and Linda has 286 beads.

Mathematics
1 answer:
Digiron [165]2 years ago
4 0

Answer:  210 fewer beads.

Step-by-step explanation:  

All you have to do is subtract the amount Diane has by Linda. And the answer you get is how many less beads Linda has. She has 210 fewer beads than Diane.  496 - 286 = 210 is the answer.

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A piece of string 64cm long is divided into three pieces in the ratio of 1:2:5. Calculate the length of the longest piece.
sergejj [24]

Answer:

40cm is the longest piece ( not sure )

5 0
3 years ago
Y=3x+14<br> 2x-3y=-14<br> Substitution method
Montano1993 [528]

Answer:

x = -8

Step-by-step explanation:

y = 3x + 14

2x - 3y = -14

So, what is the substitution? Y of course, this is because y is equal to 3x + 14.

2x - 3 (3x + 14) = -14

Multiply 3 with the numbers in the parentheses.

2x - 9x + 42 = -14

So you maybe be wondering why it is a negative 7 instead of subtracting 9 with 2. Using PEMDAS, we always read from left to right. So it is basically 2 -9 and you get -7.

-7x + 42 = -14

Then subtract 42 from both sides.

-7x + 42 - 42 = -14 - 42

Simplify

-7x = -56

Divide 7 by both sides.

-7x / 7 = -56 / 7

x = -8

And you might ask, why we get x instead afterwards. This is because both -7 and 7 cancel each other out leaving us with x.

4 0
2 years ago
Read 2 more answers
Help meez 40 pts use surface area formula of cylinder that is for Lateral surface area and for total surface area
jeka94

Answer:So the radius of the cylinder is 2.65 cm.

A cylinder can be defined as a solid figure that is bound by a curved surface and two flat surfaces. The surface area of a cylinder can be found by breaking it down into 2 parts:

1.  The two circles that make up the caps of the cylinder.

2.  The side of the cylinder, which when "unrolled" is a rectangle.

The area of each end cap can be found from the radius r of the circle, which is given by:

A = πr2

Thus the total area of the caps is 2πr2.

The area of a rectangle is given by:

A = height × width

The width is the height h of the cylinder, and the length is the distance around the end circles, or in other words the perimeter/circumference of the base/top circle and is given by:

P = 2πr

Thus the rectangle's area is rewritten as:

A = 2πr × h

Combining these parts together we will have the total surface area of a cylinder, and the final formula is given by:

A = 2πr2 + 2πrh

where:

π  is Pi, approximately 3.142

r  is the radius of the cylinder

h  height of the cylinder

By factoring 2πr from each term we can simplify the formula to:

A = 2πr(r + h)

The lateral surface area of a cylinder is simply given by: LSA = 2πr × h.

Example 1: Find the surface area of a cylinder with a radius of 4 cm, and a height of 3 cm.

Solution:

SA = 2 × π × r2 + 2 × π × r × h

SA = 2 × 3.14 × 42 +  2 × 3.14 × 4 × 3

SA = 6.28 × 16 + 6.28 × 12

SA = 100.48 + 75.36

SA = 175.84

Surface area = 175.84 cm2

Example 2: Find the surface area of the cylinder with a radius of 5.5cm and height of 10cm.

Solution:

The radius of cylinder = 5.5 cm.

The height of cylinder = 10 cm.

The total surface area of the cylinder is therefore:

TSA = 2πr(r+h)

TSA = 11π (5.5+10)

TSA = 170.5 π

TSA = 535.6 cm2

Example 3: Find the total surface area of a cylindrical tin of radius 17 cm and height 3 cm.

Solution:

Again as in the previous example:

TSA = 2πr(r+h)

TSA = 2π× 17(17+3)

TSA = 2π×17×20

TSA = 2136.56 cm2

Example 4: Find the surface area of the cylinder with radius of 6 cm and height of 9 cm.

Solution:

The radius of cylinder: r = 6 cm

The height of cylinder: h = 9 cm

Total surface area of cylinder is therefore:

TSA = 2πr(r + h)

TSA = 12π (6+9)

TSA = 180 π

TSA = 565.56 cm2

Example 5: Find the radius of cylinder whose lateral surface area is 150 cm2 and its height is 9 cm.

Solution:

Lateral surface area of cylinder is given by:

LSA = 2πrh

Given that:

LSA = 150cm2

h = 9cm

π is the constant and its value = 3.14

Substitute the values in the formula and find the value of r by isolating it from the equation:

LSA = 2πrh

150 = 2× π × r × 9

r = 150 / (2×9× π)

r = 2.65cm

So the radius of the cylinder is 2.65 cm.

5 0
2 years ago
Can someone please solve this?
forsale [732]
|-8-6|=|-14|=14
4 0
3 years ago
The cost of one pound of bananas is greater than $0.41 and less than $0.50. Sarah pays $3.40 for x pounds of bananas. Which ineq
vredina [299]

Answer:

0.41<3.40/x<0.50

Step-by-step explanation:

Given that the cost of one pound of bananas is greater than $0.41 and less than $0.50. That is,

If the cost of one banana is P, then, the inequality will be

0.41 < P < 0.50

Sarah pays $3.40 for x pounds of bananas. The inequality that represents the range of possible pounds purchased will be achieved by below

3.40/0.41 = 8.29

3.40/0.50 = 6.8

Therefore, the inequality that represents the range of possible pounds purchased is

6 < x < 9 this is the same as 0.41<3.40/x<0.50

6 0
3 years ago
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