check the picture below. So the parabola looks more or less like so.
bearing in mind that the distance "p" is the same from the vertex to the directrix or the focus point, so the vertex is therefore half-way between those two fellows, now, from 3,4 up to y = 8, there are 4 units, and the vertex is half-way, thus is at y = 6, and x = 3, (3, 6) as you see there in the picture.
the parabola is vertical, meaning the squared variable is the "x", and is opening downwards, meaning the "p" distance is negative, so since "p" is 2 units, then p = -2.
![\bf \textit{parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=3\\ k=6\\ p=-2 \end{cases}\implies 4(-2)(y-6)=(x-3)^2\implies -8(y-6)=(x-3)^2 \\\\\\ y-6=\cfrac{(x-3)^2}{-8}\implies \blacktriangleright y=-\cfrac{1}{8}(x-3)^2+6 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bparabola%20vertex%20form%20with%20focus%20point%20distance%7D%0A%5C%5C%5C%5C%0A4p%28y-%20k%29%3D%28x-%20h%29%5E2%0A%5Cqquad%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Avertex%5C%20%28%20h%2C%20k%29%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%0A%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Cbegin%7Bcases%7D%0Ah%3D3%5C%5C%0Ak%3D6%5C%5C%0Ap%3D-2%0A%5Cend%7Bcases%7D%5Cimplies%204%28-2%29%28y-6%29%3D%28x-3%29%5E2%5Cimplies%20-8%28y-6%29%3D%28x-3%29%5E2%0A%5C%5C%5C%5C%5C%5C%0Ay-6%3D%5Ccfrac%7B%28x-3%29%5E2%7D%7B-8%7D%5Cimplies%20%5Cblacktriangleright%20y%3D-%5Ccfrac%7B1%7D%7B8%7D%28x-3%29%5E2%2B6%20%5Cblacktriangleleft)
Answer:
B
Step-by-step explanation:
Slope of the line
(y2 - y1)/(x2 - x1)
(4-2)/(2-1)
2/1 =2
y = 2x
We can use y2-y1/x2-x1 to find the slope. Therefore, we have:
-5-(-13)/8-(-4). That gives us -5+13/8+4, or 8/12 = 2/3.
Hope this helps!
First convert all to decimal.
7/9 = 0.777
8/11 = 0.727
0.79 = 0.79
84% = 0.84
4/5 = 0.8
Now line them back up in order from least to greatest based on the decimal value.
Final answer:
8/11, 7/9, 0.79, 4/5, 84%
Answer:
ab<6 units
Step-by-step explanation:
One of the basic property of any triangle is that the sum of the length of any two sides of a triangle is always greater than the length of the third side.
Here we are given a triangle abc, in whicn bc=4
ac= 8-ab
If have to make some conclusion about ab.
As per the property discussed above
ab<ac+bc
ab<8-ab+4
2ab<12
ab<6
Hence the length of ab must be less than 6 units
