Xy Uefa the most important things to be a good idea for
It is the first time I have a
As the world to be able to do this
It The new version is the first of all time, and the first time since I do not have a good time and money on what will happen to have been in A
28 062 ÷ 3
9 354
9 354 x 3
28062
Average = (A₁+A₂+A₃+A₄+A₅)/5. Since average = 20 (GIVEN), then:
20 = (A₁+A₂+A₃+A₄+A₅)/5
Or (A₁+A₂+A₃+A₄+A₅) = 20x5
(A₁+A₂+A₃+A₄+A₅) = 100
=7x^4+15x^3+4y^2 I hope this helps!!
Answer:
Let X be the number of times the target is hit. The probability P(X≥1) then equals 1 minus the probability of missing the target three times:
P(X≥1) = 1− (1−P(A)) (1−P(B)) (1−P(C))
= 1−0.4*0.3*0.2
= 0.976
To find the probability P(X≥2) of hitting the target at least twice, you can consider two cases: either two people hit the target and one does not, or all people hit the target. We find:
P(X≥2)=(0.4*0.7*0.8)+(0.6*0.3*0.8)+(0.6*0.7*0.2)+(0.6*0.7*0.8) = 0.788
Step-by-step explanation: