Help, please asap loll ty

Mathematics

1 answer:

mixas84 [53]3 years ago

6 0

5. It’s y=4
6. It’s going to be y=19

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32=32+? I need help its annoyings

Andreyy89

Answer:

Step-by-step explanation:

32=32+0

5 0

3 years ago

Read 2 more answers

Find the average value of the function on the given interval.<br> f(x)=(2x-1)1/2; [1,13]

Leni [432]

Answer:

The average value of the function on the given interval 6.5.

Step-by-step explanation:

Consider the given function is

$f(x)=\dfrac{2x-1}{2}$

We need to find the average value of the function on the given interval [1,13].

$f(x)=\dfrac{2x}{2}-\dfrac{1}{2}$

$f(x)=x-0.5$

The average value of the function f(x) on [a,b] is

$Average=\dfrac{1}{b-a}\int\limits^b_a {f(x)} \, dx$

Average value of the function on the given interval [1,13] is

$Average=\dfrac{1}{13-1}\int\limits^{13}_{1} {x-0.5} \, dx$

$Average=\dfrac{1}{12}[\dfrac{x^2}{2}-0.5x]^{13}_{1}$

$Average=\dfrac{1}{12}[\dfrac{(13)^2}{2}-0.5(13)-(\dfrac{(1)^2}{2}-0.5(1))]$

$Average=\dfrac{1}{12}[78-0]$

$Average=6.5$

Therefore, the average value of the function on the given interval 6.5.

6 0

3 years ago

Another question I need help with. I've got the part where it says to rewrite as a radical expression on my paper, but I'm havin

Alik [6]

$\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\
-------------------------------\\\\
32^{\frac{3}{5}}\implies \sqrt[5]{32^3}\qquad 
\begin{cases}
32=2\cdot 2\cdot 2\cdot 2\cdot 2\\
\qquad 2^5
\end{cases}\implies \sqrt[5]{(2^5)^3}\implies \sqrt[5]{(2^3)^5}
\\\\\\
2^3\implies 8$