2 years ago

Need HELP!!!!

Mathematics

2 answers:

padilas [110]2 years ago

6 0

Answer:

Can you give me more ☆O☆

tino4ka555 [31]2 years ago

3 0

Answer:

80.07

Step-by-step explanation:

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goblinko [34]

Answer:

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Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

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Variable separable

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$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

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Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

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WARRIOR [948]

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Step-by-step explanation:

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