∠DGC and ∠CGB are _ angles.

Mathematics

2 answers:

Komok [63]3 years ago

8 0

Answer:complimentsry

Step-by-step explanation:

Vikentia [17]3 years ago

5 0

Answer: Adjacent

Step-by-step explanation:

Complementary means angles summing upto 90°

Vertical means opposite angles

Supplementary means angles summing upto 180°

So, the resonable answer will be adjacent since both the angles are beside each other.

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7x - 4 and 5x + 4 are the lengths of two of the sides of a rhombus. What is the value of x? If there is not enough information t

Mariulka [41]

Answer:

All the sides of a rhombus are equal and opposite sides parallel and equal.

Therefore by understanding the above we can deduce that:

7x - 4 = 5x + 4

7x - 4 + 4 - 5x = 5x + 4 + 4 - 5x (Separate all the terms with x to go to the other side of the equals sign and do the some for the constants).

7x - 5x + (4 - 4) = (5x - 5x) + 4 + 4

7x - 5x = 4 + 4

2x = 8

2x/2 = 8/2

x = 4

4 0

2 years ago

Read 2 more answers

Determine the given pair of lines of parallel, perpendicular, or intersecting.

podryga [215]

$k:\ y=m_1\cdot x+b_1\ \ \ \ and\ \ \ \ l:\ y=m_2\cdot x+b_2 \\\\k\ ||\ l\ \ \ \Leftrightarrow\ \ \ m_1=m_2\ \ \ \ \ \ and \ \ \ \ \ \ k\ \bot\ l\ \ \ \Leftrightarrow\ \ \ \ m_1\cdot m_2=-1\\----------------------------\\1.\\ k:\ y= \frac{7}{3} x-8\ \ \ and\ \ \ l:\ y=\frac{7}{3} x+3\\\\m_1=m_2=\frac{7}{3}\ \ \ \Rightarrow\ \ \ k\ ||\ l$

$2.\\k:\ y=2x-1\ \ and\ \ l:\ -x+2y=6\ \Rightarrow\ \ 2y=x+6\ \ \Rightarrow\ \ y= \frac{1}{2}x+3 \\\\m_1 \neq m_2\ \ \ and\ \ \ m_1\cdot m_2 \neq -1\ \ \ \Rightarrow\ \ \ the\ lines\ intersect\\\\3.\\k:\ y= \frac{5}{2} x-17\ \ \ and\ \ \ l:\ y=- \frac{5}{2} x-1\ \ \ \Rightarrow\ \ \ the\ lines\ intersect\\\\4.\\k:\ y= \frac{5}{2} x-4\ \ and\ \ l:\ -5x+2y=6\ \Rightarrow \ 2y=5x+6\ \Rightarrow \ y= \frac{5}{2}x +3\\\\m_1=m_2= \frac{5}{2} \ \ \ \Rightarrow\ \ \ k\ ||\ l$

$5.\\k:\ y=- \frac{2}{3} x+12\ \ \ and\ \ l:\ y= \frac{3}{2} x+3\\\\m_1\cdot m_2=- \frac{2}{3}\cdot \frac{3}{2} =-1\ \ \ \Rightarrow\ \ \ k\ ||\ l\\\\6.\\k:\ y= \frac{1}{3}x-13\ \ \ and\ \ \ l:\ y=3x+2\ \ \ \Rightarrow\ \ \ the\ lines\ intersect \\\\7.\\k:\ y=-4x+5\ \ ,\ \ l: -x+4y=-16\ \Rightarrow\ 4y=x-16\ \Rightarrow\ y= \frac{1}{4}x-4 \\\\m_1\cdot m_2=-4\cdot \frac{1}{4} =-1\ \ \ \Rightarrow\ \ \ k\ \bot\ l$

$8.\\k:\ y= \frac{2}{3} x+3 \ ,\ \ l:\ -2x+3y=21 \ \Rightarrow\ \ 3y=2x+21\ \Rightarrow\ y= \frac{2}{3} x+7\\\\m_1=m_2= \frac{2}{3} \ \ \ \Rightarrow\ \ \ k\ ||\ l$

8 0

3 years ago

Select the reason why these triangles are similar. If they are not, select “not similar”

larisa [96]

Answer:

B. SAS

Step-by-step explanation:

3/1= 2.25/075

The 2 sides are congruent and the angle between them is common

B. SAS is the answer

8 0

3 years ago