Answer:
4G/5G.
Explanation:
The broadband cellular network technology that mobile platforms utilize to stream voice, IP telephony, mobile internet access, video calling, gaming services, cloud computing, high-definition mobile TV, and mobile 3-D TV is 4G/5G.
4G technology refers to the fourth generation broadband cellular network technology that is typically used for cellular communications on mobile phones and it is considered to have an internet speed that is ten times faster than what is obtainable on the third generation (3G) broadband technology.
Similarly, 5G is the fifth generation broadband cellular network technology that succeeded 4G and it offers higher quality in terms of performance, reliability, availability and efficiency.
As a result of the speed and high quality specifications of the 4G/5G broadband cellular network technology, they are widely used for various communications systems.
Answer:
The two type of electronic components are Active components and passive components
Active components are parts of a circuit that rely on an external power source to control or modify electrical signals. ... - Passive components like resistors, transformers, and diodes don't need an external power source to function. These components use some other property to control the electrical signal.
Answer:
Hi there! Please find the answer below.
Explanation:
The program below demonstrates how each of the requirements can be coded in a simple Python script. To copy the array, we can use the copy() method of the array. To calculate the diff, we can use a few different techniques, so I have implemented it using a loop over the arrays and just storing and displaying the difference in the 2 arrays.
new_string.py
def add_test_score(score):
test_score.append(score);
contact_hash = {}
test_score = []
print("Enter 5 test scores: ");
for x in range(0, 5):
input_string = input("Enter test score " + str(x + 1) + ": ")
add_test_score(int(input_string));
print(test_score);
test_score_copy = test_score.copy();
for e in test_score_copy:
if e < 60:
test_score_copy[test_score_copy.index(e)] += 10;
diff = [];
for e in test_score:
print(test_score[test_score.index(e)]);
print(test_score_copy[test_score.index(e)]);
if not test_score[test_score.index(e)] == test_score_copy[test_score.index(e)]:
diff.append(e);
print(diff);
C, a video solution that is adaptable to the users storage space
The NETP provides actionable recommendations to implement
technology and conduct research and development successfully that can advance
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Hope this helps :)
