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sergeinik [125]
3 years ago
6

10 times as much as 72.67

Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

726.7 hope this helps

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Can someone help me get this please???
jarptica [38.1K]

Answer:

With respect to the reference angle, one leg is the adjacent leg, or the leg right next to the reference angle; and the other leg is the opposite leg, or the leg on the opposite side of the triangle. If two triangles are similar, the ratios of corresponding sides are equal.

5 0
3 years ago
What is the function, domain, and range??<br> {(1,-2), (-2,0), (-1,2), (1,3)}
scoundrel [369]

Answer:

the relation is NOT a function

domain: { 1,-2,1}

range:  { -2, 0, 2, 3}

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
catering service offers 8 ​appetizers, 11 main​ courses, and 7 desserts. A banquet committee is to select 7 ​appetizers, 8 main​
guapka [62]

Answer:  The required number of ways is 46200.

Step-by-step explanation:  Given that a catering service offers 8 ​appetizers, 11 main​ courses, and 7 desserts.

A banquet committee is to select 7 ​appetizers, 8 main​ courses, and 4 desserts.

We are to find the number of ways in which this can be done.

We know that

From n different things, we can choose r things at a time in ^nC_r ways.

So,

the number of ways in which 7 appetizers can be chosen from 8 appetizers is

n_1=^8C_7=\dfrac{8!}{7!(8-7)!}=\dfrac{8\times7!}{7!\times1}=8,

the number of ways in which 8 main courses can be chosen from 11 main courses is

n_2=^{11}C_8=\dfrac{11!}{8!(11-8)!}=\dfrac{11\times10\times9\times8!}{8!\times3\times2\times1}=165

and the number of ways in which 4 desserts can be chosen from 7 desserts is

n_3=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.

Therefore, the number of ways in which the banquet committee is to select 7 ​appetizers, 8 main​ courses, and 4 desserts is given by

n=n_1\times n_2\times n_3=8\times165\times35=46200.

Thus, the required number of ways is 46200.

7 0
4 years ago
How many different triangles can be constructed with angle measurements 90°, 45°, 50°?
melisa1 [442]
The angles of a triangle always add up to 180°

90+45+50=185

No triangles can be constructed
6 0
4 years ago
The diameter of 0 gauge copper wire is 8.252 mm. Find the resistance (in ω) of a 2.40 km length of such wire used for power tran
VashaNatasha [74]

d = diameter of the copper wire = 8.252 mm

r = radius of the copper wire = d/2 = 8.252 mm /2 = 4.126 mm = 0.004126 m

A = area of cross-section of the copper wire = πr² = (3.14) (0.004126)² = 53.5 x 10⁻⁶

L = length of the copper wire = 2.40 km = 2400 m

ρ = resistivity of copper wire = 1.68 x 10⁻⁸

resistance of copper wire is given as

R = ρL/A

inserting the above values in the formula

R = ( 1.68 x 10⁻⁸)(2400)/(53.5 x 10⁻⁶)

R = 0.753 ohm

8 0
4 years ago
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